如何从C#中的字符串列表创建正则表达式?

时间:2017-02-08 21:16:32

标签: c#

我有以下代码,我从字符串列表创建一个正则表达式,这完全满足我的需要。我想知道是否有一个单行方式这样做?

using System;

    class Program
    {
        static void Main(string[] args)
        {

            string[] idlist1 = new string[] { };
            string[] idlist2 = new string[] { };
            string[] idlist3 = new string[] { };
            string id1 = "ABC1234.PIL.5.0-00028-P-1";
            string id2 = "DEF5678.PIL.5.0-00028-E-1";
            string id3 = "GHI9101.PIL.4.0-00135-B-1";

            idlist1 = id1.Split('-');
            idlist2 = id2.Split('-');
            idlist3 = id3.Split('-');
            //create a regex of type ABC1234.PIL.5.0*P*
            //create a regex of type DEF5678.PIL.5.0*E*
            //create a regex of type GHI9101.PIL.4.0.B*
            string regex1 = idlist1[0] + "*" + idlist1[2] + "*" ;
            string regex2 = idlist2[0] + "*" + idlist2[2] + "*";
            string regex3 = idlist3[0] + "*" + idlist3[2] + "*";
            Console.WriteLine(regex1);
            Console.WriteLine(regex2);
            Console.WriteLine(regex3);
            Console.ReadLine();

        }
    }

3 个答案:

答案 0 :(得分:2)

一个班轮?当你可以将这个操作移动到一个方法时,这似乎是一个不必要的优化...

public string GetRegex(string idString)
{
    string[] idlist = new string[] { };
    idlist = idString.Split('-');
    string regex = idlist[0] + "*" + idlist[2] + "*";
    return regex;
}

答案 1 :(得分:0)

转到@Callback Kid的回答:

   public string GetRegex(string idString)
   {
      string[] idlist = { };
      idlist = idString.Replace('-', '*').Split('*');
      return string.Concat(idlist[0], idlist[2]);
    }

答案 2 :(得分:0)

这是您问题中所有代码的单线解决方案:)

new string[] {"ABC1234.PIL.5.0-00028-P-1", "DEF5678.PIL.5.0-00028-E-1", "GHI9101.PIL.4.0-00135-B-1"}.Select(x => Regex.Replace(x, "-.+-(.)-.", "*$1*")).ToList().ForEach(x => Console.WriteLine(x));

虽然,为了更好地理解它。 。

new string[]
{
    "ABC1234.PIL.5.0-00028-P-1", "DEF5678.PIL.5.0-00028-E-1", "GHI9101.PIL.4.0-00135-B-1"
}
.Select(x => Regex.Replace(x, "-.+-(.)-.", "*$1*"))
.ToList()
.ForEach(x => Console.WriteLine(x));

对于单个条目的实际创建,您可以使用这一个内容

Console.WriteLine(Regex.Replace("ABC1234.PIL.5.0-00028-P-1", "-.+-(.)-.", "*$1*"))