Question

我有一个看起来像这样的文本文件：

777
3
100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000010000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000100000000000000000000000000000000000000000000000000000000000000000000010000000000000000000000000000000000000000000000000000000
010000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000010000000000000000000000000000000000000000000000000000000000000000000001000000000000000000000000000000000000000000000000000000
001000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000010000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000010000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000010000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001000000000000000000000000000000000000000000000000000000000000000000000100000000000000000000000000000000000000000000000000000

前两行是数据的维度，对于此特定示例，有3行数据和777列（或每行中的值）。

我需要将这些数据读入Matlab并将结果存储为整数数组。即。我的数组将是3行x 777列，看起来像这样：

H = [
1 0 0 0 ...
0 1 0 0 ...
0 0 1 0 ...
]

我在使用特定尺寸读取数据时遇到问题，并且还从文件中取出前两个值。我所做的只是尝试读取数据而不是维度只是删除了前两行，但我宁愿不这样做。我粘贴了下面尝试的代码，我尝试了两种不同的方法，但没有得到预期的结果：

% Method 1
H = textread('myTextFile.txt', '%s');
ncols = size(H, 1);
nrows = size(H{1}, 2);
H = reshape(sscanf([H{:}], '%1d'), ncols,nrows);

% Method 2
fid = fopen('myTextFile.txt', 'r');
H = textscan(fid,'%777s');
fclose(fid);

Answer 1

我会使用fopen，feof，fgetl，str2double和两个循环来设计一段适合您特定问题的代码：

% Open file.
fid = fopen('myTextFile.txt', 'r');
% Initialize row index for H.
a = 1;
% Initialize number of line counter for file.
nline = 1;
% Test for end-of-file.
while ~feof(fid)
    % Read line from file as string.
    line = fgetl(fid);
    % Test for number of line geater than 2.
    if(nline > 2)
        % Loop through every character from the string.
        % b is column index for H.
        for b = 1:length(line)
            % Extract char from the string, convert it to double and store it in H.
            H(a, b) = str2double(line(b));
        end
        % Increase row index for H.
        a = a + 1;
    end
    % Increase number of line counter.
    nline = nline + 1;
end
% Close file.
fclose(fid);

Answer 2

这是我创建的一些代码，它从文件中读取行并将它们存储到整数数组中：

string str = "";
string str2 = ""; // To store load address for .

// myfile.open(argv[1]); // opening file
ifstream read1; // iostream variable named read1
file1.open(argv[1]);
// Memory will initialize itself by reading a program file.

cout << "File name: " << argv[1] << endl;
if(file1.is_open()) {
    cout << "File Open!" << endl;
}
while(file1.good()) // Read till end of file
{
    getline(file1, str); // Read string
    //cout << str << endl;

    if(isdigit(str[0]))
    {
        number[c++] = atoi(str.c_str()); // write(address, data) - writes 
                                         // the data to the address
    }
}

如何在文本文件中读取一定长度的数据并在matlab中存储整数数组

2 个答案: