Question

我似乎无法让这个工作。我试图用字母“T”替换任何空格，以将我的字符串转换为日期格式，但我似乎无法使其工作。我的数组工作在console.log时可以看到它是yyyy-MM-ddTHH：mm格式。但是当我把它连接到ng-repeat过滤器时，它什么也没做。这是我的代码和指向JSbin https://jsbin.com/nesedenoce/edit?html,js,console,output

的链接

HTML

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.3.15/angular.min.js"></script>
  <title>date filter</title>
</head>
<body>
  <div ng-app="test" ng-controller="controller">
  <table class="table table-bordered table-striped">
    <tr id="theader">
      <thead>
        <th>Talk Title</th>
        <th>Start Time</th>
        <th>End Time</th>
      </thead>
      </tr>
    <tr ng-repeat="item in returnedObj  | dateFilter "> 
      <td>{{item.presentation.title}}</td>
      <td>{{item.presentation.start_time | date: "h:mm a"}}</td>    
      <td>{{item.presentation.end_time | date: "h:mm a"}}</td>
    </tr>
    </table>
  </div>
</body>
</html>

JS

var app = angular.module('test', []);
app.controller("controller", ['$scope', function($scope){

  $scope.returnedObj = [{"presentation":{"title":"Introduction to Algebra",
                                      "persons":{"1":{"id":22,"start_time":"2017-05-19 08:00","end_time":"2017-05-19 08:20"},
                                      "speakers":[{"firstname":"Charles","lastname":"Hardin"}]}}}];
 }]);

  app.filter('dateFilter', function(){
        return function(item){
             var correctTimeFilter = item.filter(function(i){               
                if(i.presentation.start_time || i.presentation.end_time){           
                    console.log(i.presentation.start_time.replace(/\s/g, 'T'));
                    console.log(i.presentation.end_time.replace(/\s/g, 'T'));
                    return i.presentation.start_time.replace(/\s/g, 'T');
                    return i.presentation.end_time.replace(/\s/g, 'T');
                }
                else 
                    return null;
            })
            return correctTimeFilter;  
        }
    });

Answer 1

你正在读错你的对象。你试图从他们不是的地方获取价值。

当您将其格式化时更清晰：

$scope.returnedObj = [{
  "presentation":{
    "title":"Introduction to Algebra",
    "persons":{
      "1":{
        "id":22,"start_time":"2017-05-19 08:00","end_time":"2017-05-19 08:20"
      },
      "speakers":[{
        "firstname":"Charles","lastname":"Hardin"
      }]
    }
  }
}];

Here是使用T替换日期中的空格的代码段，如果这是你想要做的。

此外，您不能按照在过滤器功能中尝试的顺序返回2个值。

角度过滤器替换3d数组中的字符串

1 个答案: