Question

我有一个MySql查询，如下所示：

SELECT o.id, 
       o.priorytet_1 + 
       o.priorytet_2 +
       o.priorytet_3 AS bonus 
FROM obiekty o 
WHERE o.ac=1 
GROUP BY o.id 
ORDER BY `o`.`id` ASC

priorytet_1, priorytet_2 and priorytet_3列旁边的priorytet_1_valid, priorytet_2_valid, priorytet_3_valid我存储了日期，例如priorytet_1有效。

我想只添加那些日期为< now()的列。

类似的东西：

SELECT o.id, 
       if (o.priorytet_1_valid < now()) o.priorytet_1 + 
       if (o.priorytet_2_valid < now()) o.priorytet_2 + 
       if (o.priorytet_3_valid < now()) o.priorytet_3 AS bonus 
FROM obiekty o 
WHERE o.ac=1 
GROUP BY o.id 
ORDER BY `o`.`id` ASC

感谢您的帮助！

Answer 1

尝试：

SELECT o.id, 
       SUM(IF (o.priorytet_1_valid < NOW(), o.priorytet_1, 0) + 
           IF (o.priorytet_2_valid < NOW(), o.priorytet_2, 0) + 
           IF (o.priorytet_3_valid < NOW(), o.priorytet_3, 0)) AS bonus
FROM obiekty o 
WHERE o.ac=1 
GROUP BY o.id 
ORDER BY `o`.`id` ASC

您可能希望使用SUM，因为您有GROUP BY子句。上面的查询中使用的SUM函数有条件地会添加字段o.priorytet_1, o.priorytet_2, o.priorytet_3，以防相应的有效＆＃39;字段早于当前日期/时间。

如果condition列为true，则添加值

1 个答案: