Question

假设我有：

 __________________________________
| ID |   NAME   |       ITEM        |
-----------------------------------
| 2 |   John   |        vlc        |
````````````````````````````````````
| 3 |   mike   |        vlc        |
````````````````````````````````````
| 4 |   ali    |        vlc        |
````````````````````````````````````
| 5 |   Insan  |        vlc        |
````````````````````````````````````
| 6 |   Hawai  |        vlc        |
````````````````````````````````````
| 7 |   Jack   |        vlc        |
````````````````````````````````````
| 8 |   Chan   |        vlc        |
````````````````````````````````````

现在我有一个查询：

SELECT NAME FROM table WHERE ITEM='vlc' LIMIT 2

您可能知道这会选择第一行和第二行，因为我将其限制为最多选择两行，因此结果为John和Mike。

问题：

我想要的是在两个第一行之后选择2行，例如ali和Insan。如：

SELECT NAME FROM table WHERE ITEM='vlc' LIMIT 2 but after 2 first rows

或

SELECT NAME FROM table WHERE ITEM='vlc' LIMIT 2 but after 5 first rows

感谢所有事情：）

Answer 1

使用OFFSET

SELECT NAME FROM table WHERE ITEM='vlc' LIMIT 2 OFFSET 5

您可以使用不带OFFSET的简短查询和使用逗号的LIMIT，如下所示

SELECT NAME FROM table WHERE ITEM='vlc' LIMIT 5,2

请注意，在第二种方法中，首先是OFFSET值，然后是LIMIT值

Answer 2

您也可以使用

SELECT NAME FROM table WHERE ITEM='vlc' LIMIT 2, 2

Answer 3

在mysql中，您可以使用LIMIT with OFFSET

SELECT NAME FROM table WHERE ITEM='vlc' LIMIT 2 OFFSET 2

这将返回以第三个值

开头的2个值

如何在mysql中x行数之后选择行？

3 个答案: