Question

我有这张桌子：

persnid  |  elemntref |   val
   100   |     1      |   5000
   100   |     2      |   2500
   100   |     3      |   3100

我想使用以下条件：

IF elemntref = 1 THEN create new column that name is 'pay'
IF elemntref = 2 THEN create new column that name is 'pay2'
IF elemntref = 3 THEN create new column that name is 'pay3'

运行查询后的

表：

   persnid  |  Pay   |   Pay2  |    pay3    
     100    | 5000   |   2500  |    3100

Answer 1

你想要一个CASE

SELECT persnid
        ,SUM(CASE WHEN elemntref = 1 THEN ISNULL(val,0) END) AS pay
        ,SUM(CASE WHEN elemntref = 2 THEN ISNULL(val,0) END) AS pay2
        ,SUM(CASE WHEN elemntref = 3 THEN ISNULL(val,0) END) AS pay3
FROM YOUR_TABLE
GROUP BY persnid

Answer 2

如果elemntref列值固定为1,2,3，则正常枢轴工作

<强>架构：

SELECT * INTO #TAB1 FROM (
SELECT 100 PERSNID, 1 ELEMNTREF, 5000 VAL
UNION ALL
SELECT 100, 2 , 2500
UNION ALL
SELECT 100, 3, 3100
)A

现在以1,2,3作为列进行旋转

SELECT PERSNID, [1] AS PAY, [2] AS PAY2, [3] AS PAY3 FROM (
SELECT * FROM #TAB1
)A
PIVOT
(
SUM(VAL) FOR ELEMNTREF IN ([1],[2],[3])
)PVT

结果将是

+---------+------+------+------+
| PERSNID | PAY  | PAY2 | PAY3 |
+---------+------+------+------+
|     100 | 5000 | 2500 | 3100 |
+---------+------+------+------+

Answer 3

如果行数未知，您也可以使用动态SQL查询执行此操作。

<强>查询

declare @sql as varchar(max);
select @sql = 'select [persnid], ' 
+ stuff((select distinct  ', coalesce(sum(case [elemntref] when ' +  
   cast([elemntref] as varchar(50)) +  
   ' then [val] end), 0) as [pay' + cast([elemntref] as varchar(10)) + ']'
   from [your_table_name]
for xml path('')
), 1, 2, '')
+' from [your_table_name] group by [persnid]';

exec(@sql);

如果字段等于值，则在sql中创建新列

3 个答案: