Question

我的实体产品包含featureTypes的Arraycollection（ManytoMany）类产品：

/**
 * @var FeatureType
 *
 * @ORM\ManyToMany(targetEntity="AppBundle\Entity\FeatureType", mappedBy="products")
 */
private $featureTypes;

public function __construct()
{
    $this->variants = new ArrayCollection();
    $this->featureTypes = new ArrayCollection();
}

类FeatureType：

/**
 * @var Product[]|ArrayCollection
 *
 * @ORM\ManyToMany(targetEntity="AppBundle\Entity\Product", inversedBy="featureTypes")
 * @ORM\JoinTable(name="products_featureTypes")
 */
private $products;

现在我想创建一个表单，它可以呈现所有可用featureType的下拉列表。我想选择一个并提交它。

我在addFeatureTypeToProductType中尝试了这样：

public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder
        ->add('featureTypes', EntityType::class, [
            'class' => FeatureType::class,
            'choice_label' => 'name',
        ])
        ->add('submit', SubmitType::class)
        ->getForm();
}

输出是具有所有可用FeatureType的下拉列表。但是当我提交所选的featureType时，我收到一个错误：“无法确定属性'featureType'的访问类型。”

然后我试着这样：

public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder
        ->add('featureTypes', CollectionType::class, [
            'entry_type' => FeatureType::class,
            'allow_add' => true,
        ])
        ->add('submit', SubmitType::class)
        ->getForm();
}

但这不起作用

我的控制器：

public function addFeatureTypeAction(Request $request, Product $product)
{
    $form = $this->createForm(AddFeatureTypeToProductType::class, $product, [
        'action' => $this->generateUrl('admin_products_add_featureTypes', [
            'product' => $product->getId()
        ])
    ]);

    $form->handleRequest($request);


    if($form->isSubmitted() && $form->isValid()) {
        $featureType = $form->get('featureTypes');
        $product->addFeatureTypes($featureType);
        $em = $this->getDoctrine()->getManager();
        $em->persist($product);
        $em->flush();

        return $this->redirectToRoute('admin_products_list_all');
    }

    return [
        'form' => $form->createView()
    ];
}

对不起我的英文：S

编辑：这是我的加法器/移除器和设置器/吸气器：

/**
 * @return FeatureType
 */
public function getFeatureTypes()
{
    return $this->featureTypes;
}

/**
 * @param FeatureType $featureTypes
 */
public function setFeatureTypes($featureTypes)
{
    $this->featureTypes = $featureTypes;
}


/**
 * Add new FeatureType
 *
 * @param FeatureType $featureType
 *
 * @return Product
 */
public function addFeatureTypes($featureType)
{
    if (!$this->featureTypes->contains($featureType)) {
        $this->featureTypes->add($featureType);
    }

    return $this;
}

/**
 * @param FeatureType $featureType
 *
 * @return Product
 */
public function removeFeatureTypes($featureType)
{
    if ($this->featureTypes->contains($featureType)) {
        $this->featureTypes->remove($featureType);
    }

    return $this;
}

编辑2：我用我表格的第一种方式再试一次。但我现在得到一个新的错误。我不知道为什么我的实体“FeatureType”不知道contains方法。它使用Symfony Arraycollection

错误：尝试调用类“AppBundle \ Entity \ FeatureType”的名为“contains”的未定义方法。

调试在addFeatureTypes（$ featureType）

中停止

我现在更进一步了。现在，我使用collectionType。

 public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder
        ->add('featureTypes', CollectionType::class, [
            'entry_type' => FeatureTypeType::class,
            'allow_add' => true,
        ])
        ->add('submit', SubmitType::class)
        ->getForm();
}

我的前端表单显示了我的产品已有的所有featureTypes。但我不知道，如何添加新的......

Answer 1

我的属性的注释是错误的。类产品：

/**
 * @var FeatureType[]|ArrayCollection
 *
 * @ORM\ManyToMany(targetEntity="AppBundle\Entity\FeatureType", inversedBy="products", cascade={"persist"})
 * @ORM\JoinTable(name="products_featureTypes")
 */
private $featureTypes;

类FeatureType：

/**
 * @var Product[]|ArrayCollection
 *
 * @ORM\ManyToMany(targetEntity="AppBundle\Entity\Product", mappedBy="featureTypes", cascade={"persist"})
 *
 */
private $products;

我的表格：

public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder
        ->add('featureTypeToAdd', EntityType::class, [
            'class'        => FeatureType::class,
            'choice_label' => 'name',
            'mapped'       => false,
        ])
        ->add('submit', SubmitType::class)
        ->getForm();
}

我的控制器：

 public function addFeatureTypeAction(Request $request, Product $product)
{
    $form = $this->createForm(AddFeatureTypeToProductType::class, $product, [
        'action' => $this->generateUrl('admin_products_add_featureTypes', [
            'product' => $product->getId(),
        ]),
    ]);

    $form->handleRequest($request);

    if ($form->isSubmitted() && $form->isValid()) {
        $featureType = $form->get('featureTypeToAdd')->getData();
        $em = $this->getDoctrine()->getManager();
        $product->addFeatureTypes($featureType);
        $em->persist($product);
        $em->flush();

        return $this->redirectToRoute('admin_products_list_all');
    }

    return [
        'form' => $form->createView(),
    ];
}

Symfony FormType，从Arraycollection获取Dropdown

1 个答案: