Question

我尝试使用以下代码尝试从下拉菜单中调用PHP函数。

这样做有干净的方法吗？

码

<html>
<head>
</head>
<body>
   <?php
     function OnSelectionChange() {
       echo("OK IT WORKS");
     }    
  ?>
  <section>
    <select onchange="OnSelectionChange()">
      <option value='' disabled selected>Assign Driver</option>
      <option value='4353'>Steve Jobs</option>
      <option value='3333'>Ian Wright</option>
      <option value='66666'>Mark James</option>
    </select>
  </section>    
</body>
</html>

Answer 1

使用jquery的简单ajax

索引页

<!DOCTYPE html>
<html>
    <head>
        <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
        <script>
            $(document).ready(function(){
            $('#myDropDown').change(function(){
                //Selected value
                var inputValue = $(this).val();
                alert("value in js "+inputValue);

                //Ajax for calling php function
                $.post('submit.php', { dropdownValue: inputValue }, function(data){
                    alert('ajax completed. Response:  '+data);
                    //do after submission operation in DOM
                });
            });
        });
        </script>
    </head>
<body>
    <select id="myDropDown">
        <option value='' disabled selected>Assign Driver</option>
        <option value='4353'>Steve Jobs</option>
        <option value='3333'>Ian Wright</option>
        <option value='66666'>Mark James</option>
     </select>

</body>
</html>

在submit.php中

<?php
function processDrpdown($selectedVal) {
    echo "Selected value in php ".$selectedVal;
}        

if ($_POST['dropdownValue']){
    //call the function or execute the code
    processDrpdown($_POST['dropdownValue']);
}

对于简单的js ajax使用XMLHttpRequest

Answer 2

您可以在不使用JavaScript的情况下使用php从下拉列表中获取所选值。

＆＃13;

<html>
<head>
<title>Country</title>
</head>
<body>
<form>
    Select Your Country 
    <select name="country" onchange="this.form.submit()">
        <option value="" disabled selected>--select--</option>
        <option value="india">India</option>
        <option value="us">Us</option>
        <option value="europe">Europe</option>
    </select>
</form>
<?php
   if(isset($_GET["country"])){
       $country=$_GET["country"];
       echo "select country is => ".$country;
   }
?>
</body>
</html>

＆＃13;

Answer 3

不能这样做，而是使用JavaScript函数

<html>
<head>
</head>
<body>

<script>
function OnSelectionChange()
{
 alert("OK IT WORKS");
}
</script>

<section>
 <select onchange="OnSelectionChange()">
  <option value='' disabled selected>Assign Driver</option>
  <option value='4353'>Steve Jobs</option>
  <option value='3333'>Ian Wright</option>
  <option value='66666'>Mark James</option>
 </select>
</section>


</body>
</html>

Answer 4

不使用php函数连接onchange事件。必须使用javascript函数

<script>
 function OnSelectionChange()
 {
  alert("OK IT WORKS");
 }
</script>

Answer 5

<html>
<head>
<title>Country</title>
</head>
<body>
<form>
    Select Your Country 
    <select name="country" onchange="this.form.submit()">
        <option value="" disabled selected>--select--</option>
        <option value="india">India</option>
        <option value="us">Us</option>
        <option value="europe">Europe</option>
    </select>
</form>
<?php
   if(isset($_GET["country"])){
       $country=$_GET["country"];
       echo "select country is => ".$country;
   }
?>
</body>
</html>

Answer 6

<html>
<head>
<title>Country</title>
</head>
<body>
<form>
    Select Your Country 
    <select name="country" onchange="this.form.submit()">
        <option value="" disabled selected>--select--</option>
        <option value="india">India</option>
        <option value="us">Us</option>
        <option value="europe">Europe</option>
    </select>
</form>
<?php
   if(isset($_GET["country"])){
       $country=$_GET["country"];
       echo "select country is => ".$country;
   }
?>
</body>
</html>

Answer 7

这种温和的适应对我来说效果很好。非常感谢 vivekcs0114，而且很好地避免了 JS 和所需的 Ajax 解决方案，经过大约 200 次悲惨的尝试，这完全是一场灾难。

<form method="post" action="">
<select method="post" name="areasel" onchange="this.form.submit()"> 
<option value="Choose one">Choose one</option>
<option value="Complete Airframe">Complete Airframe</option>
<option value="Armstrong Siddeley">Armstrong Siddeley</option>
<option value="Something">Something</option>
</select>
</form>
<?php
if(isset($_POST["areasel"]))
{
$type=$_POST["areasel"];
echo "<BR>Do some SQL stuff using :".$type;
}
?>

下载onchange调用PHP函数

7 个答案: