从eclipse运行时代码工作正常但是在使用maven创建war并使用maven进行部署后,它显示了以下预期,因此在文件放置的位置,即使在部署战争之后也可以访问它。
<ns0:ServiceCall2Response xmlns:ns0="http://files/">
<return><![CDATA[<Response><RESP_STTS>800</RESP_STTS><RESP_DESC>java.io.FileNotFoundException: src\main\resources\config.properties (The system cannot find the path specified)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.<init>(FileInputStream.java:146)
at java.io.FileInputStream.<init>(FileInputStream.java:101)
at files.DownloadDocInFileImpl.ServiceCall2(DownloadDocInFileImpl.java:124)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:606)
at weblogic.wsee.jaxws.WLSInstanceResolver$WLSInvoker.invoke(WLSInstanceResolver.java:117)
at weblogic.wsee.jaxws.WLSInstanceResolver$WLSInvoker.invoke(WLSInstanceResolver.java:91)
at com.sun.xml.ws.server.InvokerTube$2.invoke(InvokerTube.java:149)
at com.sun.xml.ws.server.sei.SEIInvokerTube.processRequest(SEIInvokerTube.java:88)
at com.sun.xml.ws.api.pipe.Fiber.__doRun(Fiber.java:1136)
at com.sun.xml.ws.api.pipe.Fiber._doRun(Fiber.java:1050)
at com.sun.xml.ws.api.pipe.Fiber.doRun(Fiber.java:1019)
at com.sun.xml.ws.api.pipe.Fiber.runSync(Fiber.java:877)
at com.sun.xml.ws.server.WSEndpointImpl$2.process(WSEndpointImpl.java:419)
at com.sun.xml.ws.transport.http.HttpAdapter$HttpToolkit.handle(HttpAdapter.java:868)
at com.sun.xml.ws.transport.http.HttpAdapter.handle(HttpAdapter.java:422)
at com.sun.xml.ws.transport.http.servlet.ServletAdapter.handle(ServletAdapter.java:169)
at weblogic.wsee.jaxws.WLSServletAdapter.handle(WLSServletAdapter.java:199)
at weblogic.wsee.jaxws.HttpServletAdapter$AuthorizedInvoke.run(HttpServletAdapter.java:640)
at weblogic.security.acl.internal.AuthenticatedSubject.doAs(AuthenticatedSubject.java:363)
at weblogic.security.service.SecurityManager.runAs(SecurityManager.java:146)
at weblogic.wsee.util.ServerSecurityHelper.authenticatedInvoke(ServerSecurityHelper.java:108)
at weblogic.wsee.jaxws.HttpServletAdapter$3.run(HttpServletAdapter.java:284)
at weblogic.wsee.jaxws.HttpServletAdapter.post(HttpServletAdapter.java:293)
at weblogic.wsee.jaxws.JAXWSServlet.doRequest(JAXWSServlet.java:128)
at weblogic.servlet.http.AbstractAsyncServlet.service(AbstractAsyncServlet.java:99)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:844)
at weblogic.servlet.internal.StubSecurityHelper$ServletServiceAction.run(StubSecurityHelper.java:280)
at weblogic.servlet.internal.StubSecurityHelper$ServletServiceAction.run(StubSecurityHelper.java:254)
at weblogic.servlet.internal.StubSecurityHelper.invokeServlet(StubSecurityHelper.java:136)
at weblogic.servlet.internal.ServletStubImpl.execute(ServletStubImpl.java:346)
at weblogic.servlet.internal.ServletStubImpl.execute(ServletStubImpl.java:243)
at weblogic.servlet.internal.WebAppServletContext$ServletInvocationAction.wrapRun(WebAppServletContext.java:3432)
at weblogic.servlet.internal.WebAppServletContext$ServletInvocationAction.run(WebAppServletContext.java:3402)
at weblogic.security.acl.internal.AuthenticatedSubject.doAs(AuthenticatedSubject.java:321)
at weblogic.security.service.SecurityManager.runAs(SecurityManager.java:120)
at weblogic.servlet.provider.WlsSubjectHandle.run(WlsSubjectHandle.java:57)
at weblogic.servlet.internal.WebAppServletContext.doSecuredExecute(WebAppServletContext.java:2285)
at weblogic.servlet.internal.WebAppServletContext.securedExecute(WebAppServletContext.java:2201)
at weblogic.servlet.internal.WebAppServletContext.execute(WebAppServletContext.java:2179)
at weblogic.servlet.internal.ServletRequestImpl.run(ServletRequestImpl.java:1572)
at weblogic.servlet.provider.ContainerSupportProviderImpl$WlsRequestExecutor.run(ContainerSupportProviderImpl.java:255)
at weblogic.work.ExecuteThread.execute(ExecuteThread.java:311)
at weblogic.work.ExecuteThread.run(ExecuteThread.java:263)
检验.pdf]] GT;
答案 0 :(得分:0)
您需要在pom.xml中指定资源
<resources>
<resource>
<directory>${project.basedir}/src/main/resources</directory>
<filtering>true</filtering>
</resource>
</resources>
http://maven.apache.org/plugins/maven-resources-plugin/examples/resource-directory.html
或强> 使用Maven war Plugin和资源
<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-war-plugin</artifactId>
<version>3.0.0</version>
<configuration>
<webResources>
<resource>
<directory>src/main/resources</directory>
</resource>
</webResources>
</configuration>
</plugin>
</plugins>
</build>
正在加载属性
import java.io.IOException;
import java.util.Properties;
public class PropertiesUtil {
private static void loadProperties() {
Properties properties = new Properties();
try {
properties.load(PropertiesUtil.class.getResourceAsStream("/config.properties"));
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
答案 1 :(得分:0)
不要使用FileInputStream
来阅读这些属性。如果您希望配置成为WAR文件的一部分,则需要确保它在类路径中打包并可用。
例如,如果您正在使用maven,请将config.propertues
文件放在src/main/resources
文件夹中。这将与代码一起打包,并且可以在运行时在类路径上访问,并且可以像这样访问:
InputStream s = WhateverClassInYourProject.class.getResourceAsStream("/config.properties");
Properties props = new Properties();
props.load(inputStream);