Question

我目前正在做一个项目。我有一个复选框（用户将选择公司提供的服务类型）。当我尝试在我的控制器中发布所选的服务（例如，检查了2个服务）时，我只获得一项服务。问题是如何在复选框中获取多个值？

注意：我也尝试在我的控制器中使用foreach，我收到一些错误，例如“为foreach（）提供的无效参数”。

查看

<label>Desired Service</label> <br>
<?php foreach($services as $s):?>
<label><input type="checkbox" name="service_name[]" value="<?= $s->service_name?>"><?= $s->service_name?></label>
<br> 
<?php endforeach?>

控制器

$this->form_validation->set_error_delimiters('<div class="alert alert-danger" role="alert">', '</div>');
    $this->form_validation->set_rules('full_name', 'Fullname', 'required');
    $this->form_validation->set_rules('email', 'Email', 'required');
    $this->form_validation->set_rules('contact', 'Contact', 'required');
    $this->form_validation->set_rules('date', 'Date', 'required');
    $this->form_validation->set_rules('address', 'Address', 'required');
    $this->form_validation->set_rules('zip_code', 'Zip Code', 'numeric|required');
    $this->form_validation->set_rules('province', 'Province', 'required');
    $this->form_validation->set_rules('date', 'Date', 'required');
    $this->form_validation->set_rules('service_name', 'Service', 'required');
    if ($this->form_validation->run() == FALSE) {
        $this->index();
    } 
    else {
        $service_name = implode(', ', $_POST['service_name']);
        $event = array(
        'full_name' => $this->input->post('full_name'),
        'email' => $this->input->post('email'),
        'contact' => $this->input->post('contact'),
        'address' => $this->input->post('address'),
        'zip_code' => $this->input->post('zip_code'),
        'state_province' => $this->input->post('province'),
        'date' => $this->input->post('date'),
        'service' => $service_name

        );
        $this->EventModel->add_event($event);
        echo "<script>
        window.alert('Your Desired Date is being Proccessed!');
        location.href = '".site_url('/')."';
        </script>";
    }

Answer 1

从

改变

$service_name = $_POST['service_name'];
foreach($service_name as $key =>$value)
{
    echo $value;
}
die;

到

$service_name = implode(',',$_POST['service_name']);
echo $service_name;

Answer 2

我希望它能解决你的问题

if (!empty($this->input->post('service_name'))) {
        foreach ($this->input->post('service_name') as $key => $val) {
            $data[] = array(
            'service_name' => $_POST['service_name'][$key]
        );
}
foreach ($data as $item) {    
       echo $item['service_name'];
}

Answer 3

尝试：

$service_name = $this->input->post('service_name');

for($i=0;$i < count($service_name);$i++){
    echo $service_name[$i];
}

在codeigniter中获取多个复选框值

3 个答案: