python中的标准石头剪刀代码

Question

player1 = raw_input("Player 1? ")
player2 = raw_input("Player 2? ")

if ((player1 != "rock" or
    player1 != "paper" or
    player1 != "scissors") and
    (player2 != "rock" or
    player2 != "paper" or
    player2 != "scissors")):
    if (player1 == 'rock' and player2 == 'rock'):
        print 'Tie.'
    if (player1 == 'paper' and player2 == 'paper'):
        print 'Tie.'
    if (player1 == 'scissors' and player2 == 'scissors'):
        print 'Tie.'
    if (player1 == 'paper' and player2 == 'rock'):
        print 'Player 1 wins.'
    if (player1 == 'rock' and player2 == 'scissors'):
        print 'Player 1 wins.'
    if (player1 == 'scissors' and player2 == 'paper'):
        print 'Player 1 wins.'
    if (player1 == 'rock' and player2 == 'paper'):
        print 'Player 2 wins.'
    if (player1 == 'scissors' and player2 == 'rock'):
        print 'Player 2 wins.'
    if (player1 == 'paper' and player2 == 'scissors'):
        print 'Player 2 wins.'
else:
    print "This is not a valid object selection."

上面是代码，出于某种原因，当你输入的东西不是摇滚，纸张或剪刀时，else语句永远不会打印出来。有人可以帮我这个吗？

Answer 1

条件!=需要更改为==

player1 = raw_input("Player 1? ")
player2 = raw_input("Player 2? ")

if ((player1 == "rock" or
    player1 == "paper" or
    player1 == "scissors") and
    (player2 == "rock" or
    player2 == "paper" or
    player2 == "scissors")):
    if (player1 == 'rock' and player2 == 'rock'):
        print 'Tie.'
    if (player1 == 'paper' and player2 == 'paper'):
        print 'Tie.'
    if (player1 == 'scissors' and player2 == 'scissors'):
        print 'Tie.'
    if (player1 == 'paper' and player2 == 'rock'):
        print 'Player 1 wins.'
    if (player1 == 'rock' and player2 == 'scissors'):
        print 'Player 1 wins.'
    if (player1 == 'scissors' and player2 == 'paper'):
        print 'Player 1 wins.'
    if (player1 == 'rock' and player2 == 'paper'):
        print 'Player 2 wins.'
    if (player1 == 'scissors' and player2 == 'rock'):
        print 'Player 2 wins.'
    if (player1 == 'paper' and player2 == 'scissors'):
        print 'Player 2 wins.'
else:
    print "This is not a valid object selection."

Answer 2

您的第一个myRecyclerView.setLayoutManager(new LinearLayoutManager(getContext(), LinearLayoutManager.VERTICAL, false){ @Override public boolean canScrollHorizontally() { return false; } @Override public boolean canScrollVertically() { return false; } }); 语句将始终评估为if。将true替换为!=，您会很高兴。

Answer 3

您可以使用in。

player1 = raw_input("Player 1? ")
player2 = raw_input("Player 2? ")

valid_opts = {'rock', 'paper', 'scissors'}
if player1.lower() in valid_opts and player2.lower() in valid_opts:
    ...
else:
    print("invalid input")

Answer 4

正如其他人所指出的，您需要将多个!=更改为==。您可能还会考虑一些缩短：

if len(set(player1, player2, "rock", "paper", "scissors")) == 3:
    if player1 == player2:
        print 'Tie.'
    answers = ["Player 1 wins.", "Player 2 wins."]
    elif player1 == "rock":
        print answers[player2=="paper"]
    elif player1 == "paper":
        print answers[player2=="scissors"]
    elif player1 == "scissors":
        print answers[player2=="rock"]
else:
    print "This is not a valid object selection."

Answer 5

您可以使用dict和一系列if/elif/else语句简化整个程序：

priority = dict(rock='scissors', paper='rock', scissors='paper')

player_1 = raw_input('Player 1? ')
player_2 = raw_input('Player 2? ')

if player_1 not in priority or player_2 not in priority:
    print 'This is not a valid object selection.'
elif player_1 == player_2:
    print 'Tie.'
elif priority[player_1] == player_2:
    print 'Player 1 wins.'
else:
    print 'Player 2 wins.'

只需一点点工作，如果您愿意，可以让代码适应RPSSL的规则：

priority = dict(scissors={'paper', 'lizard'},
                paper={'rock', 'spock'},
                rock={'lizard', 'scissors'},
                lizard={'spock', 'paper'},
                spock={'scissors', 'rock'})

player_1 = raw_input('Player 1? ')
player_2 = raw_input('Player 2? ')

if player_1 not in priority or player_2 not in priority:
    print 'This is not a valid object selection.'
elif player_1 == player_2:
    print 'Tie.'
elif player_2 in priority[player_1]:
    print 'Player 1 wins.'
else:
    print 'Player 2 wins.'