Question

似乎我还不够清楚。似乎有效的查询是：

Select ((Select count (table1.id) from table1  where table1.code=2 and table1.name=5) as ‘name5’,
(Select count (table1.id) from table1  where table1.code=2 and table1.name=7) as ‘name7’)
From table.1;
union
Select ((Select count (table1.id) from table1  where table1.code=5 and table1.name=5) as ‘name5’,
(Select count (table1.id) from table1  where table1.code=5 and table1.name=7) as ‘name7’)

From table.1;
union
Select ((Select count (table1.id) from table1  where table1.code=15 and table1.name=5) as ‘name5’,
(Select count (table1.id) from table1  where table1.code=15 and table1.name=7) as ‘name7’)
From table.1;

...

得到这样的结果：

name5  name7
    52         47
    42         84
    61         11

我的问题是table1.code除了2,5和15之外还有一千个以上的值，我不能重复一次这样的联合语句。

Answer 1

好吧，您似乎只想按代码列中的值进行分组，并且可以使用IN或EXISTS

export class SecureComponent implements OnInit {
  userRole:any;
  role:string = 'MEMBER';
  constructor(private userService: UserService,private router:Router) {
  }

  ngOnInit() {

    this.role = 'MEMBER';
    console.log('Role',this.userRole);

    if (!this.userService.isLoggedIn()) {
      this.router.navigateByUrl('/login');
    }
  }
}

输出将是

select count(table1.id) as theCount, table1.code as theCode
 from table1 where table1.code in ('code a','code b', 'etc...')
group by table1.code;

或类似的东西，但非计数的非名义数字 HTH

Answer 2

您可以尝试列出嵌套选择列表中从a到您的值的所有值，例如： 100，就像那样：

select count table1.id from table1 one where table1.code in (
     select rownum from all_objects where rownum < 100
);

或者如果你不想从“1”开始：

select count table1.id from table1 one where table1.code in (
    select rownum n from dual connect by level 10 where n>3
);

ORACLE SQL重复同样的查询

2 个答案: