如何使用java replaceAll（regex，replacement）方法掩盖字符串中的最后一个括号括号？

Question

我想

ASDFASDFG => A********
(qwe)rtya(sdfg)h => (qwe)rtya(s***)h

所以我试着

public String setMask_ (String name_){

    String result = null;

    if(name_.lastIndexOf("(") > -1) {
        // Bracket Begin 
        int locBrkBgn = name_.lastIndexOf("(") +2;
        // Bracket End 
        int locBrkEnd = locBrkBgn + (name_.substring(locBrkBgn, name_.length())).indexOf(")") -1;
        // result = name_.replaceAll("(?<=.{"+locBrkBgn+"}).*(?={"+locBrkEnd+"})", "*");
        result = name_.replaceAll("(?<=\\().*?(?=\\))", "*");
    } else {
        result = name_.replaceAll("(?<=.{1}).", "*");
    }
    return result;
}

Answer 1

哦，我想我做到了。

public String setMask_ (String name_){

    String result = null;

    if(name_.lastIndexOf("(") > -1) {
        // locate. Bracket Begin 
        int locBrkBgn = name_.lastIndexOf("(") +2;
        result = name_.replaceAll("(?<=.{"+locBrkBgn+"}).(?=[^\\)]*?\\))", "*");
    } else {
        result = name_.replaceAll("(?<=.{1}).", "*");
    }
    return result;
}

Answer 2

result = name_.replaceAll（“\（\ w + \）\ w * $”，“（”+ name_.replaceAll（“\（\ w \）\ w * \（\ w * \）“，”）“））;

基本上，用*替换第二个括号内的部分，然后用闭括号括号替换所有内容直到最后一个右括号。