我在openfire中通过安装open fire插件从openfire获取了History并尝试了这段代码。
let iq1 = DDXMLElement(name: "iq")
iq1.addAttribute(withName: "type", stringValue: "get")
iq1.addAttribute(withName: "id", stringValue: "0")
let retrieve = DDXMLElement(name: "retrieve", xmlns: "urn:xmpp:archive")
retrieve?.addAttribute(withName: "with", stringValue: "raman@ip-172-31-53-77.ec2.internal")
let set = DDXMLElement(name: "set", xmlns: "http://jabber.org/protocol/rsm")
let max = DDXMLElement(name: "max", stringValue: "50")
iq1.addChild(retrieve!)
retrieve?.addChild(set!)
set?.addChild(max)
stream?.send(iq1 )
现在我没有从双方获得历史。这是我得到的结果。
<iq xmlns="jabber:client"
type="result"
id="0"
to="bentick@ip-172-31-53-77.ec2.internal/5qsinh1syg">
<chat xmlns="urn:xmpp:archive"
with="raman@ip-172-31-53-77.ec2.internal"
start="2017-02-07T06:28:33.691Z">
<from secs="0">
<body>hello</body>
</from>
<from secs="405">
<body>hiii</body>
</from>
<from secs="580">
<body>Hey</body>
</from>
<from secs="599">
<body>HooooE</body>
</from>
<from secs="628">
<body>hOo</body>
</from>
<from secs="907">
<body>Raman here</body>
</from>
<from secs="931">
<body>Raman here ONE</body>
</from>
<from secs="1273">
<body>Raman here</body>
</from>
<from secs="1558">
<body> Raman from SPark </body>
</from>
<from secs="1571">
<body> Raman from SPark One</body>
</from>
<from secs="1782">
<body>Raman from SPark </body>
</from>
<from secs="2651">
<body>Raman FiVE</body>
</from>
<from secs="2810">
<body>Raman Three</body>
</from>
<from secs="2810">
<body>Raman FOur</body>
</from>
<from secs="3534">
<body>RAMAN SIX</body>
</from>
<from secs="4105">
<body>Raman OKK</body>
</from>
<from secs="4113">
<body>OKKK l</body>
</from>
<from secs="4130">
<body>UST</body>
</from>
<set xmlns="http://jabber.org/protocol/rsm">
<first index="0">0</first>
<last>17</last>
<count>18</count>
</set>
</chat>
</iq>
&#13;
这是RAMAN而不是BENTICk的所有消息,因为这两个用户在获取历史时参与聊天我只得到RAMAN的消息。不是BENTICk 如何从双方用户获取历史记录。
请帮忙。
答案 0 :(得分:-1)
我已经实现了相同的功能,通过发送给定的iq来获取消息 我得到了正确的结果。
let iQ = DDXMLElement.element(withName: "iq") as! DDXMLElement
iQ.addAttribute(withName: "type", stringValue: "get")
iQ.addAttribute(withName: "id", stringValue: (xmppHandler.xmppStream?.generateUUID())!)
let retrieve = DDXMLElement(name: "retrieve", xmlns: "urn:xmpp:archive")
retrieve?.addAttribute(withName: "with", stringValue: "\(JID!)@\(Utility.hostname)")
let set = DDXMLElement.element(withName: "set") as! DDXMLElement
set.addAttribute(withName: "xmlns", stringValue: "http://jabber.org/protocol/rsm")
let max = DDXMLElement.element(withName: "max") as! DDXMLElement
max.stringValue = "10"
max.addAttribute(withName:"xmlns", stringValue: "http://jabber.org/protocol/rsm")
iQ.addChild(retrieve!)
retrieve?.addChild(set)
set.addChild(max as DDXMLNode)
xmppHandler.xmppStream?.send(iQ)
<iq type="get" id="7705EEC5-3385-42D4-B748-B39C204ADB90"><retrieve xmlns="urn:xmpp:archive" with="0544008296@192.168.2.181"><set xmlns="http://jabber.org/protocol/rsm"><max xmlns="http://jabber.org/protocol/rsm">10</max></set></retrieve></iq>
响应
<iq xmlns="jabber:client" type="result" id="7705EEC5-3385-42D4-B748-B39C204ADB90" to="0509503847@192.168.2.181/Smack">
<chat xmlns="urn:xmpp:archive" with="0544008296@192.168.2.181" start="2017-02-28T09:55:27.068Z">
<from secs="0" jid="0544008296@192.168.2.181">
<body>Hiii rajeev</body>
</from>
<to secs="52">
<body>Hi
How r u</body>
</to>
<from secs="15" jid="0544008296@192.168.2.181"><body>I am good</body></from>
<to secs="8"><body>What abt u</body></to>
<to secs="169"><body>Hello testing chat</body></to>
<from secs="10" jid="0544008296@192.168.2.181"><body>Good</body></from>
<from secs="5" jid="0544008296@192.168.2.181"><body>Continue </body></from>
<to secs="834"><body>Ok
</body></to>
<to secs="8"><body>Nice chat
</body></to>
<from secs="232" jid="0544008296@192.168.2.181"><body>Heelo</body></from>
<set xmlns="http://jabber.org/protocol/rsm"><first index="0">0</first> <last>9</last><count>574</count></set></chat></iq>