Question

我试图用一个非常简单的代码来检测笔记本电脑架构。下面是代码。我的笔记本电脑是64位，但它也会显示32位消息框。代码还有什么遗漏吗？

#Load assembly
add-type -assemblyname system.windows.forms

#Assign messagebox to variable
$message1 = [System.Windows.Forms.MessageBox]::Show("This is a 64 bit     version" , "Status")
$message2 = [System.Windows.Forms.MessageBox]::Show("This is a 32 bit version" , "Status")

#Display message based on the architecture
if ([System.Environment]::Is64BitProcess) {
echo $message1
} else {
echo $message2
}

Answer 1

您的消息框在变量声明本身时运行，您可以通过仅运行$x = [System.Windows.Forms.MessageBox]::Show("This is a 64 bit version" , "Status")语句来确认。显示消息框并存储消息的响应（＆＃34; ok＆＃34 ;在这种情况下）在变量中，试试这个：

#Load assembly
add-type -assemblyname system.windows.forms


#Display message based on the architecture
if ([System.Environment]::Is64BitProcess) {
[System.Windows.Forms.MessageBox]::Show("This is a 64 bit     version" , "Status")
} else {
[System.Windows.Forms.MessageBox]::Show("This is a 32 bit version" , "Status")
}

检测系统架构

1 个答案: