使用列表中的单词对字符串进行排序

Question

我希望按字符串（行）的长度对单词进行排序，然后在列表中按每行中单词的数量对它们进行排序。

list_of_words = ['hoop t','hot op','tho op','ho op t','phot o']

所以输出结果为：

hoot t
phot o
hot op
tho op
ho op t

Answer 1

如果我已经正确理解了你想要完成的任务，那就可以做到：

pin = 0
#...
        this_pair = idx1*5 + idx2
        pin = pin * 100 + this_pair

print(pin)

list_of_words = ['hoop t','hot op','tho op','ho op t','phot o']

# first sort the words in each string by their length, from longest to shortest
for i, words in enumerate(list_of_words):
    list_of_words[i] = sorted(words.split(), key=len, reverse=True)

# second sort the list by how many words there are in each sublist
list_of_words.sort(key=lambda words: len(words))  # sorts list in-place

# third, join the words in each string back together into a single string
for i, words in enumerate(list_of_words):
    list_of_words[i] = ' '.join(words)

# show results
print(list_of_words)