无法在C中找到剩余部分

Question

程序应该将用户输入的分钟数转换为天，小时和分钟

 #include <stdio.h>

 int main(void) {



 int input_minutes, minutes, r_minutes;  
 int days, hours;
 float r_days, r_hours;


 printf("Enter a number of minutes: ");
 scanf("%d", &input_minutes); 

 days = input_minutes / 1440;

这里是我希望将input_minutes的剩余部分除以1440，而是在编译时得到160.00007。

 r_days =  input_minutes % 1440;
 hours = r_days * 24;
 r_hours = (r_days * 1440) - hours;
 minutes = r_hours * 60; 

 printf("r_days = %f", r_days);

 printf("This represents:%d days, %d hours, %d minutes\n",days, hours,        minutes);

Answer 1

此处没有合理的理由使用float类型（除了整数模数外，不涉及除法）。使用浮动只会导致精度损失和问题代表＆amp;正如您所经历的那样正确显示整数。

的quickfix：

int r_days, r_hours;

和

printf("r_days = %d", r_days);

另见：Is floating point math broken?

Answer 2

您可能想要更改计算小时和分钟的逻辑。天计算似乎没问题。

r_days =  input_minutes % 1440;
hours = r_days/60;
minutes = r_days % 60;
printf("This represents:%d days, %d hours, %d minutes\n",days, hours, minutes);