Question

我有两个错误，我找不到任何方法来解决它们

警告：mysqli_query期望至少有2个参数，1个给出

查询错误：SELECT ID，TITLE，CONTENT，AUTHOR，DATE FROM NEWS ORDER BY ID DESC。

<?php
     include("site.inc.php");

        db_login();

    //Generate the query so we can retrieve all titles in the DB in descending ID order


  $query = 'SELECT `id`, `title`, `content`, `author`, `date` FROM `news` ORDER BY `id` DESC';
  $result = mysqli_query($query) 
      or die ("Error in query: $query. " . mysqli_connect_error());

      // if records are present
if (mysql_num_rows($result) > 0) {

    while($send = mysql_fetch_object($result)) {
?> 
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>test</title>
</head>
<table cellpadding="0" cellspacing="0">
<tr>
<td>
<?php 
echo"$send->content";


 ?>
</td>
</tr>
<tr>
<?Php
echo "$send->author";
}
}
?>

</tr>
<br>

</table>

function db_login

<?php


$confg['db_uname'] = "root";      
$confg['db_paswd'] = "";      
$confg['db_host'] = "localhost";  
$confg['db_dbase'] = "dbname";     



function db_login() {

global $confg;

$link = @mysqli_connect($confg['db_host'], $confg['db_uname'], $confg['db_paswd']) or die("Error connecting: " . mysql_error());

@mysqli_select_db($confg['db_dbase'], $link);
mysqli_query($link,"set names 'utf8';");
}



function db_logout() {

@mysqli_close($link);

}

?>

Answer 1

添加指向执行

的链接

 $result = mysqli_query($link, $query) 
      or die ("Error in query: $query. " . mysqli_connect_error());

Answer 2

您需要在使用mysqli_query()时传递连接字符串。

您的查询应如下所示：

$query = 'SELECT `id`, `title`, `content`, `author`, `date` FROM `news` ORDER BY `id` DESC';
$result = mysqli_query($link, $query) or die ("Error in query: $query. " . mysqli_connect_error());

mysqli_query至少需要2个参数

2 个答案: