Question

我是PHP的新手。我想在数组的每个对象中添加数组。它是数组内部的数组，每个数组对象都包含一个数组。我也在互联网上搜索我没有找到与此相关的任何内容。

这是我的愿望json

[{  
      "id":1,
      "name":"Grey",
      "list":[  
         {  
            "id":1,
            "name":"60 X 60 ABC"
         },
         {  
            "id":2,
            "name":"40 X 40 PQR"
         },
         {  
            "id":3,
            "name":"45 X 45 XYZ"
         }
      ]
   },
   {  
      "id":2,
      "name":"Yarn",
      "list":[  
         {  
            "id":4,
            "name":"YARN ABC"
         },
         {  
            "id":5,
            "name":"YARN XYZ"
         }
      ]
   }]

所有这些数据都是从mysql数据库中填充的。

这是我的PHP代码

$sql = "select * from tblType";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    while($rows = $result->fetch_assoc()) {

        $obj = new stdClass;

        $obj->id = $rows["id"];
        $obj->name = $rows["name"];
        $obj->list = $array2;

        $sql2 = "select * from tblQuality where typeId = $obj->id";
            $result2 = $conn->query($sql2);

            if ($result2->num_rows > 0) {
                while($row = $result2->fetch_assoc()) {
                    $obj2 = new stdClass;

                    $obj2->id = $row["id"];
                    $obj2->name = $row["name"];

                    array_push($array2, $obj2);
                }
            }
        array_push($array, $obj);
    }
}

echo json_encode($array);

mysqli_close($conn);

我不知道如何在数组中添加数组。请帮忙。

Answer 1

试试这个：

<?php

/* 
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */
$sql = "select * from tblType";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    while($rows = $result->fetch_assoc()) {

        $obj = new stdClass;

        $obj->id = $rows["id"];
        $obj->name = $rows["name"];
        $obj->list = array();

        $sql2 = "select * from tblQuality where typeId = $obj->id";
            $result2 = $conn->query($sql2);

            if ($result2->num_rows > 0) {
                while($row = $result2->fetch_assoc()) {
                    $obj2 = new stdClass;

                    $obj2->id = $row["id"];
                    $obj2->name = $row["name"];

                    array_push( $obj->list, $obj2);
                }
            }
        array_push($array, $obj);
    }
}

echo json_encode($array);

mysqli_close($conn);

Answer 2

你在这里：

$sql = "select * from tblType";
$result = $conn->query($sql);

$results = [];

if ($result->num_rows > 0) {
    while($rows = $result->fetch_assoc()) {
        $item = [];
        $item['id'] = $rows['id']
        $item['name'] = $rows['name'];
        $item['list'] = [];

        $sql2 = "select * from tblQuality where typeId = " . $rows['id'];
        $result2 = $conn->query($sql2);

        if ($result2->num_rows > 0) {
            while($row = $result2->fetch_assoc()) {
                $item['list'][] = [
                    'id' => $row['id'],
                    'name' => $row['name']
                ]
            }
        }

        $results[] = $item
    }
}

echo json_encode($results);

mysqli_close($conn);

提示：不要将stdClass个对象用作数组。他们不是故意的。

在php中的每个数组对象中添加数组

2 个答案: