Question

我正在构建一个允许我上传和删除图片的页面。此外，我可以在该页面上查看图片。现在，我可以上传图片，图片将存储在我的C：盘文件夹中，记录将上传到MySql。但是，我无法删除图片并查看页面上的图片。我不确定这些的原因。我猜问题可能是图片的命名和文件位置。

当我上传图片时，C：盘中的命名将根据时间更改为名称。 MySql中记录的命名仍将保持不变。

我不确定如何将这两个图像转换为相同的名称，并在MySql中提供一个路径，允许我显示图像以删除我的图片。

我的页面代码如下：

 <div class="container">
            <?php
            include "config.php";

            if (isset($_FILES['file'])) {
                //////
                if ($_FILES["file"]["error"] > 0) {
                    echo "Error: :{$_FILES["file"]["error"]}<br>";
                } else {


                    $allowdExts = ["jpg", "jpeg", "gif", "png"];
                    $filenameStrArr = explode(".", $_FILES["file"]["name"]);
                    $extension = strtolower(end($filenameStrArr));
                    ////-----------------------------
                    $name = $_FILES['file']['name'];
                    $size = $_FILES['file']['size'];
                    $type = $_FILES['file']['type'];
                    $tmp = $_FILES['file']['tmp_name'];
                    ///-------------------------------
                    $allowedTypes = ["image/jpg", "image/jpeg", "image/gif", "image/png", "image/pjpeg"];
                    $fileType = $_FILES["file"]["type"];
                    $sizeLimit = 2000;
                    $fileSize = $_FILES["file"]["size"] / 1024;  //divide to get size in kb
                    if (in_array($extension, $allowdExts) &&
                            in_array($fileType, $allowedTypes) &&
                            ($fileSize <= $sizeLimit)) {

                        $distDir = "../uploads/";
                        $distFilename = "pic_" . time() . ".{$extension}";
                        $upload = $distDir . "/" . $distFilename;

                        //$distFinal = "upload/" . $_FILES["myFile"]["name"];    
                        move_uploaded_file($_FILES['file']['tmp_name'], $upload);
                    }
                }

                /*
                  $file = '../uploads/' . $_FILES['file']['name'];
                  $upload = move_uploaded_file($tmp, $file); */

                if ($upload) {
                    $add = $db->prepare("insert into upload values('',?)");
                    $add->bindParam(1, $name);
                    if ($add->execute()) {
                        ?>
                        <div class="alert alert-success alert-dismissible" role="alert">
                            <button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">&times;</span></button>
                            <strong>Success!</strong> File upload successful to database.
                        </div>
                        <?php
                    } else {
                        ?>
                        <div class="alert alert-danger alert-dismissible" role="alert">
                            <button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">&times;</span></button>
                            <strong>Failed!</strong> File upload unsuccessful to database.
                        </div>
                        <?php
                    }
                } else {
                    ?>
                    <div class="alert alert-warning alert-dismissible" role="alert">
                        <button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">&times;</span></button>
                        <strong>Sorry!</strong> File upload unsuccessful .
                    </div>
                    <?php
                }
            }
            ?>
            <form method="post" enctype="multipart/form-data">
                <div class="form-group">
                    <label for="file">Upload File</label>
                    <input type="file" id="file" name="file">
                    <p class="help-block">This will be the picture you upload.</p>
                </div>   
                <button type="submit" class="btn btn-default">Upload</button>
            </form>

            <p><br/></p>
            <div class="row">
                <?php
                if (isset($_GET['remove'])) {
                    $img = $_GET['remove'];
                    $id = $_GET['id'];
                    $remove = unlink('uploads'.$img);
                    if ($remove) {
                        $rmv = $db->prepare("delete from upload where id='$id'");
                        if ($rmv->execute()) {
                            ?>
                            <div class="alert alert-success alert-dismissible" role="alert">
                                <button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">&times;</span></button>
                                <strong>Success!</strong> File removed from directory and database .
                            </div>
                            <?php
                        } else {
                            ?>
                            <div class="alert alert-danger alert-dismissible" role="alert">
                                <button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">&times;</span></button>
                                <strong>Failed!</strong> File failed erased from database.
                            </div>
                            <?php
                        }
                    } else {
                        ?>
                        <div class="alert alert-warning alert-dismissible" role="alert">
                            <button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">&times;</span></button>
                            <strong>Error!</strong> File is not erased from directory.
                        </div>
                        <?php
                    }
                }

                $stmt = $db->prepare("select * from upload");
                $stmt ->execute();
                while ($row = $stmt->fetch()) {
                    ?>
                    <div class="col-sm-6 col-md-4">
                        <div class="thumbnail">
                            <img style="height:200px;"src="uploads<?php echo$row['foto'] ?>" alt="<?php echo$row['foto'] ?>" title="<?php echo$row['foto'] ?>">
                            <div class="caption text-center">
                                <p><a href="?remove=<?php echo$row['foto'] ?> &id<?php echo$row['id'] ?>" class="btn btn-danger" role="button">Delete</a></p>
                            </div>
                        </div>
                    </div>
                    <?php
                }
                ?>
            </div>
        </div>

Answer 1

<强> 1。你应该删除你的删除查询。

<div class="nested-fields">
    <li>
      <%= f.label :name %>
      <%= f.text_field :name%>
      <%= link_to_remove_association 'Remover Dependente', f %>
    </li>
</div>

<强> 2。然后，您可能忘记了删除文件行中的斜杠。

变化

<?php
include '../dbh.php';

session_start(); //THIS APPEARS TO BE MISSING 

$email = $_POST['email'];
$pwd   = $_POST['pwd'];

$sql    = "SELECT * FROM user WHERE email='$email' AND pwd='$pwd'";
$result = mysqli_query($conn, $sql);

if (!$row = mysqli_fetch_assoc($result)) {
    //You have Session no matter what for this user
    $_SESSION['authenticated'] = false;
} else {
    $_SESSION['authenticated'] = true;
    $_SESSION['id'] = $row['id'];
}
header("Location: ../index.php");
?>

到

<?php
if($_SESSION['authenticated']) {
    echo $_SESSION['id'];
} else {
    echo "You are not logged in!";
}
?>

我还建议您，只从数据库中读取文件路径，而不是通过get请求。您已经获得该文件的ID了吗？使用文件ID作为主键，而不是文件名。

第3。您尝试显示图像时也会缺少/ 变化

$rmv = $db->prepare("delete from upload where id=:file_id");
$rmv->bindValue(':file_id', $id, \PDO::PARAM_INT);

到

$remove = unlink('uploads'.$img);

使用PHP和MySql上传和删除图片

1 个答案: