JPA多对多关系创建两个连接表

时间:2017-02-06 14:04:30

标签: java mysql jpa orm eclipselink

我正在尝试在UserFileObject类之间创建多对多关系,假设用户可以访问许多文件对象,并且文件对象可以被许多用户访问,并且可以访问 - 很多关系,因为一个用户可以拥有多个文件,但一个文件只能由一个用户拥有。这是我的代码:

@Entity
public class User {

    @Id
    @GeneratedValue(strategy = GenerationType.TABLE)
    public int id;
    public String firstname;
    public String lastname;
    public String publicAttributes;
    public String privateAttributes;

    @ManyToOne
    private Department department;

    @OneToMany(mappedBy = "user")
    public List<Device> devices = new ArrayList<Device>();

    @OneToMany(mappedBy = "userCreator")
    public List <FileObject> fileOwned = new ArrayList <FileObject>();

    @ManyToMany
    @JoinTable(name="USER_FILE_ACCESS")
    public List<FileObject> fileHasAccess = new ArrayList<FileObject>();
}

@Entity
public class FileObject {

    @Id
    @GeneratedValue(strategy = GenerationType.TABLE)
    public int id;
    String checksum;

    @OneToMany(mappedBy = "fileObject")
    public List<Policy> policies = new ArrayList<Policy>();

    byte[] encryptedFileKey;

    byte[] iv;

    @ManyToOne
    public User userCreator;

    @ManyToMany
    public List<User> listUserAccessor = new ArrayList<User>();
}

理论上它应该只创建一个连接表,即USER_FILE_ACCESS,但是当我运行脚本时,它会创建两个连接表,我不知道为什么。

以下是SQL命令的摘录:

show tables;
+------------------+
| Tables_in_cpabe  |
+------------------+
| DEPARTMENT       |
| DEVICE           |
| FILEOBJECT       |
| FILEOBJECT_USER  |
| POLICY           |
| SEQUENCE         |
| USER             |
| USER_FILE_ACCESS |
+------------------+

show columns from FILEOBJECT_USER;
+---------------------+---------+------+-----+---------+-------+
| Field               | Type    | Null | Key | Default | Extra |
+---------------------+---------+------+-----+---------+-------+
| FileObject_ID       | int(11) | NO   | PRI | NULL    |       |
| listUserAccessor_ID | int(11) | NO   | PRI | NULL    |       |
+---------------------+---------+------+-----+---------+-------+

show columns from USER_FILE_ACCESS;
+------------------+---------+------+-----+---------+-------+
| Field            | Type    | Null | Key | Default | Extra |
+------------------+---------+------+-----+---------+-------+
| User_ID          | int(11) | NO   | PRI | NULL    |       |
| fileHasAccess_ID | int(11) | NO   | PRI | NULL    |       |
+------------------+---------+------+-----+---------+-------+

如何使联接表只有一个表?

1 个答案:

答案 0 :(得分:3)

如果你想要双向关系,那么:

@Entity
public class User {

@ManyToMany
@JoinTable(name="USER_FILE_ACCESS"
     joinColumns=@JoinColumn(name="user_id"),
        inverseJoinColumns=@JoinColumn(name="fileHasAccess_ID "))
public Set<FileObject> fileHasAccess;


@Entity
public class FileObject {

@ManyToMany
@JoinTable(name="USER_FILE_ACCESS"
         joinColumns=@JoinColumn(name="fileHasAccess_ID"),
            inverseJoinColumns=@JoinColumn(name="user_id"))
    public Set<User> listUserAccessor;

<强>更新

尝试使用SEt而不是List。

您还可以尝试另一种双向选项。因此,在非拥有方面,您将映射如下:

@ManyToMany(mappedBy = "fileHasAccess")
public Set<User> listUserAccessor;

另外仔细检查列名称..我可能已经放了一些不同于你在db中的实际情况。