awk打印字符串没有固定宽度格式？

Question

有没有办法让awk不打印固定宽度的列？

例如：

"9", "TAYLOR TOWER, JACOB B.   "
"9", "UNIVERSITY HOSPITALS-EAST"
"AR", "SCHOTTENSTEIN CENTER     "
"B1", "NEWARK RESIDENCE HALL    "
"B2", "NEWARK RESIDENCE HALL    "
"CC", "OHIO STADIUM             "
"D1", "TELECOM NETWORK CENTER  "
"DC", "SCHOTTENSTEIN CENTER     "
"EN", "SCHOTTENSTEIN CENTER     "
"GR", "UNIVERSITY HOSPITALS-EAST"
"LL", "RANEY COMMONS, 2ND LT. AL"
"MZ", "PHYSICS RESEARCH        "
"MZ", "SCHOTTENSTEIN CENTER     "
"NS", "STARLING LOVING HALL    "
"P1", "OHIO STADIUM             "
"P2", "OHIO STADIUM             "
"P3", "OHIO STADIUM             "

我希望将其打印为：

"9", "TAYLOR TOWER, JACOB B."
"9", "UNIVERSITY HOSPITALS-EAST"
"AR", "SCHOTTENSTEIN CENTER"
"B1", "NEWARK RESIDENCE HALL"
"B2", "NEWARK RESIDENCE HALL"
"CC", "OHIO STADIUM"
"D1", "TELECOM NETWORK CENTER"
"DC", "SCHOTTENSTEIN CENTER"
"EN", "SCHOTTENSTEIN CENTER"
"GR", "UNIVERSITY HOSPITALS-EAST"
"LL", "RANEY COMMONS, 2ND LT. AL"
"MZ", "PHYSICS RESEARCH"
"MZ", "SCHOTTENSTEIN CENTER"
"NS", "STARLING LOVING HALL"
"P1", "OHIO STADIUM"
"P2", "OHIO STADIUM"
"P3", "OHIO STADIUM"

请注意，此文本中的第二个字段在引号内没有空格。这可能吗？

Answer 1

我会使用sed而不是awk，但如果你必须在awk中执行gsub：

sed -e 's/  *"$/"/'

含义“在行尾将一个或多个空格后跟引号改为引用”

Answer 2

在AWK（gawk / nawk）中

{sub(/[ ]*\"$/, "\"");print}