SequelizeDatabaseError:运算符不存在:字符变化[] @>性格变化

时间:2017-02-06 09:31:52

标签: arrays node.js postgresql multidimensional-array sequelize.js

当我尝试在数组数组中搜索一个数组值时,我收到了上述错误。我的代码:

    sequelize.define('room', {
    'id' : {'type' : DataTypes.INTEGER, 'primaryKey' : true, 'autoIncrement' : true},
    'tutor' : {'type' : DataTypes.INTEGER, 'allowNull' : false},
    'students' : {'type' : DataTypes.ARRAY(DataTypes.STRING), 'allowNull' : false},
    'subject' : DataTypes.STRING,
    'date_time' : DataTypes.DATE,
    'status' : {'type' : DataTypes.STRING , 'defaultValue' : "active"},
  }
)

var queryString = "Select * from rooms where status = :statusVar and students @> ANY(:stuArray::character varying[]) ORDER BY CASE when :orderingVar = 'date_time DESC' then date_time end DESC, case when :orderingVar = 'date_time' THEN date_time end ASC OFFSET :offsetNumber LIMIT :limitNumber;"

    return sequelize.query(queryString,{ 
                      replacements:{ 
                        statusVar: status,
                        orderingVar: orderVar, 
                        limitNumber: itemPerPage, 
                        offsetNumber: ((pageNumber-1)*itemPerPage),
                        tutArray: '{' + tutorUserId.toString() +'}',
                        stuArray: ['{' + studName.toString() + '}']
                      }, 
                        type: sequelize.QueryTypes.SELECT})

其中studName = [Emily,John,Dexter];

我想查找“学生”栏中包含任何学生姓名的所有记录,例如Emily或John或Dexter

1 个答案:

答案 0 :(得分:1)

我最终做了以下工作

var queryString = "Select * from rooms where students && :stuArray::varchar[] and status = :statusVar ORDER BY CASE when :orderingVar = 'date_time DESC' then date_time end DESC, case when :orderingVar = 'date_time' THEN date_time end ASC OFFSET :offsetNumber LIMIT :limitNumber;"

'&安培;&安培;'重叠(具有共同的元素)运算符Ex:ARRAY [1,4,3]&& ARRAY [2,1]返回true。请注意,运算符的右侧也应该是此格式的数组stuArray: ['{' + studName.toString() + '}'],即['{Emily, John, Dexter}']