Question

我的主要项目是在核心php中创建的，我正在处理一个模块，该模块位于同一项目文件夹中的codeigniter中。

$_SESSION['UserName'] = $loginDetailAr['UserName'];
$_SESSION['UserType'] = $loginDetailAr['UserType'];
$_SESSION['UserTypeName'] = $loginDetailAr['UserTypeName'];
$_SESSION['IsAdmin'] = $loginDetailAr['IsAdmin'];

Answer 1

加载会话库

$this->load->library('session');
// can access variables with this->session
$is_admin = $this->session->IsAdmin;

有关详细信息，请参阅。 https://www.codeigniter.com/user_guide/libraries/sessions.html

Answer 2

这可以帮到你

   $this->load->library('session');

$ result = $ this-＆gt; login_model-＆gt; userLogin（$ email，$ password）;

if ($result) {
    $sess_array = array();
    foreach ($result as $loginDetailAr) {
        $sess_array = array(
            'UserName' => $loginDetailAr->UserName,
            'UserType' => $loginDetailAr->UserType,
            'UserTypeName' => $loginDetailAr->UserTypeName,
            'IsAdmin' => $loginDetailAr->IsAdmin,
            );
        $this->session->set_userdata('logged_in', $sess_array);
    }
    return TRUE;
} else {
    $this->form_validation->set_message('check_database', ' Invalid Email Or Password ');
    return FALSE;
}

在codeigniter框架中调用会话，该框架已在codeigniter文件夹之外的父php文件夹中声明

2 个答案: