我正在尝试创建一个程序，可以从一副52张牌中取出两张牌。到目前为止，我已经使用switch语句将卡值分配给一个数字，例如，Ace of Spades = 0，Seven of Clubs = 26。但是，为了拥有两张牌，它们必须是唯一的，我不知道如何去做。
import java.lang.Object;
import java.util.Scanner;
import java.util.Random;
public class Deck {
public static void main(String[] args) {
Random rnd = new Random();
int cardNumber = rnd.nextInt(52);
String toCard = null;
switch (cardNumber){
case 0: toCard = "Ace of Spades";
break;
case 1: toCard = "Ace of Hearts";
break;
case 2: toCard = "Ace of Clubs";
break;
case 3: toCard = "Ace of Diamonds";
break;
case 4: toCard = "Two of Spades";
break;
case 5: toCard = "Two of Hearts";
break;
case 6: toCard = "Two of Clubs";
break;
case 7: toCard = "Two of Diamonds";
break;
case 8: toCard = "Three of Spades";
break;
case 9: toCard = "Three of Hearts";
break;
case 10: toCard = "Three of Clubs";
break;
case 11: toCard = "Three of Diamonds";
break;
case 12: toCard = "Four of Spades";
break;
case 13: toCard = "Four of Hearts";
break;
case 14: toCard = "Four of Clubs";
break;
case 15: toCard = "Four of Diamonds";
break;
case 16: toCard = "Five of Spades";
break;
case 17: toCard = "Five of Hearts";
break;
case 18: toCard = "Five of Clubs";
break;
case 19: toCard = "Five of Diamonds";
break;
case 20: toCard = "Six of Spades";
break;
case 21: toCard = "Six of Hearts";
break;
case 22: toCard = "Six of Clubs";
break;
case 23: toCard = "Six of Diamonds";
break;
case 24: toCard = "Seven of Spades";
break;
case 25: toCard = "Seven of Hearts";
break;
case 26: toCard = "Seven of Clubs";
break;
case 27: toCard = "Seven of Diamonds";
break;
case 28: toCard = "Eight of Spades";
break;
case 29: toCard = "Eight of Hearts";
break;
case 30: toCard = "Eight of Clubs";
break;
case 31: toCard = "Eight of Diamonds";
break;
case 32: toCard = "Nine of Spades";
break;
case 33: toCard = "Nine of Hearts";
break;
case 34: toCard = "Nine of Clubs";
break;
case 35: toCard = "Nine of Diamonds";
break;
case 36: toCard = "Ten of Spades";
break;
case 37: toCard = "Ten of Hearts";
break;
case 38: toCard = "Ten of Clubs";
break;
case 39: toCard = "Ten of Diamonds";
break;
case 40: toCard = "Jack of Spades";
break;
case 41: toCard = "Jack of Hearts";
break;
case 42: toCard = "Jack of Clubs";
break;
case 43: toCard = "Jack of Diamonds";
break;
case 44: toCard = "Queen of Spades";
break;
case 45: toCard = "Queen of Hearts";
break;
case 46: toCard = "Queen of Clubs";
break;
case 47: toCard = "Queen of Diamonds";
break;
case 48: toCard = "King of Spades";
break;
case 49: toCard = "King of Hearts";
break;
case 50: toCard = "King of Clubs";
break;
case 51: toCard = "King of Diamonds";
break;
}
System.out.println(cardNumber + " " + toCard);
}
}
我知道可能有更多有效的方法可以解决这个问题，但我对编码起来相对较新。我想将每个案例分配给一个数组中的索引，以便我可以调用say cardArray [0]并返回黑桃王牌，并最终从cardArray中调用两个随机数，并让它们成为唯一的卡片。
感谢任何帮助。
答案 0 :(得分：1)
为了向玩家发放两张独特的牌，你的班级设计应该与此类似：
播放器应该有一系列卡片。
([0-9]{4}(?:[1-9][0-9]|[0-9][1-9])) CardDealer 应该有一副牌和public class Player {
private String[] cards;
public String[] getCards() {
return cards;
}
public void setCards(String[] cards) {
this.cards = cards;
}
@Override
public String toString() {
return "Player [cards=" + Arrays.toString(cards) + "]";
}
}
方法，可以向给定的玩家发牌。
deal(Player... players)现在，如果你运行这样的测试：
public class CardDealer {
private static Random rand;
private static final String[] DECK = { "Ace of Spades",
"Ace of Hearts",
"Ace of Clubs",
"Ace of Diamonds",
"Two of Spades",
"Two of Hearts",
"Two of Clubs",
"Two of Diamonds",
"Three of Spades",
//etc.
};
//Use a java.util.Random object to generate random numbers.
public CardDealer(){
rand = new Random();
}
/**
* This method accepts variable number of players
* and for each player, it picks up two unique cards
* from the deck, creates an array of those two cards
* and assigns that array to the players
*/
public void deal(Player... players){
for(Player eachPlayer : players){
// Create an array of 2 cards for each player
String[] cards = new String[2];
// Pick first card randomly from deck.
int cardIndex1 = rand.nextInt(52);
String card1 = DECK[cardIndex1];
// Pick second card randomly from deck
int cardIndex2 = rand.nextInt(52);
// If the second picked index is equal to first, pick again
while(cardIndex1 == cardIndex2){
cardIndex2 = rand.nextInt(52);
}
String card2 = DECK[cardIndex2];
//Give each player his cards.
cards[0] = card1;
cards[1] = card2;
eachPlayer.setCards(cards);
}
}
}
它应该产生如下结果：
CardDealer dealer = new CardDealer();
Player sam = new Player();
Player joe = new Player();
dealer.deal(sam,joe);
System.out.println("Sam -> " + sam);
System.out.println("Joe -> " + joe);
我希望这会让你有一些想法继续进行。
答案 1 :(得分：0)
使用switch大小为String
52语句为名称分配数字。
String []cards = new String[52];
并将卡片的名称存储在此数组中。 例如
cards[0] = "Ace of Spades";
要从数组中获取任何卡，只需参考存储它的数组的索引号
cards[indexnumber];
例如
cards[0];
将返回Ace of Spades，因为它存储在数组的索引0中。
请注意，每张卡在阵列中都有唯一的索引号。
答案 2 :(得分：0)
您可以使用Set来确保您的值是唯一的：
public ArrayList<String> drawCards(int noOfCardsToDraw)
{
//set up an array of strings that represent your cards
//and can be indexed 0-51 i.e. 52 cards total.
String[] deck = {
"Ace of spades",
"two of spades",
"three of spades",
"for of spades"
//etc
};
//a set of integers ensures that you have no duplicate
//card values
Set<Integer> cardValues = new Hashset<Integer>();
//pick your random card values and add them to the set,
//if there happen to be two identical random numbers
//then inserting it into the set does nothing, so this
//will loop until your chosen number of cards have been
//picked.
while(result.size < noOfCardsToDraw)
{
cardValues.add(deck[rnd.nextInt(51)]);
}
//and arraylist of strings to hold the card designations
ArrayList<String> result = new ArrayList<String>();
//loop through the set of card values adding the corresponding
//string at that index to the arraylist.
for(int card : cardValues)
{
result.add(deck[card]);
}
//return the arraylist to do with as you please
return result;
}
这应该继续挑选随机卡，直到该集与您传入方法的数量相同。所以，如果你这样称呼它：
ArrayList<String> cards = drawCards(2);
然后您可以使用以下方法检索值：
cards.get(0) //for first element
cards.get(1) //for second element
然后你应该有两张独特的随机卡。
答案 3 :(得分：0)
static final String[] cards = {"Ace","Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Jack", "Queen", "King"};
static final String[] colors ={"Spades", "Hearts", "Clubs", "Diamonds"};
public static String getAcard(int num) {
String card = cards[num%cards.length];
String color = colors[num/cards.length];
return card + " of " + color;
}
public static void main(String[] args) {
int deckSize = cards.length * colors.length;
List<String> deck = new ArrayList<>();
for (int i=0; i<deckSize; i++) {
deck.add(getAcard(i));
}
Collections.shuffle(deck);
List<String> pair = deck.subList(0, 2);
pair.forEach( p-> System.out.println(p));
}