在django admin中保存更改时获取“请更正以下错误”

Question

使用“python manage.py inspectdb --database = mydatabasename”从以下mysql数据库创建模型：

CREATE TABLE `authors` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `name` varchar(45) DEFAULT NULL,
  `birthday` date DEFAULT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8;

CREATE TABLE `books` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `titel` varchar(45) DEFAULT NULL,
  `year` int(11) DEFAULT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8;

CREATE TABLE `authors_books` (
  `author_id` int(11) NOT NULL,
  `book_id` int(11) NOT NULL,
  KEY `fk_authors_books_2_idx` (`book_id`),
  KEY `fk_authors_books_1` (`author_id`),
  CONSTRAINT `fk_authors_books_1` FOREIGN KEY (`author_id`) REFERENCES `authors` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION,
  CONSTRAINT `fk_authors_books_2` FOREIGN KEY (`book_id`) REFERENCES `books` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

CREATE TABLE `awards` (
  `author` int(11) NOT NULL,
  `award_name` varchar(45) NOT NULL,
  `year` int(11) DEFAULT NULL,
  PRIMARY KEY (`author`,`award_name`),
  CONSTRAINT `fk_awards_1` FOREIGN KEY (`author`) REFERENCES `authors` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

模型看起来像这样：

class Authors(models.Model):
    name = models.CharField(max_length=45, blank=True, null=True)
    birthday = models.DateField(blank=True, null=True)

    class Meta:
        managed = True
        db_table = 'authors'
        verbose_name_plural = 'Authors'  

    def __unicode__(self):
        return self.name


class AuthorsBooks(models.Model):
    author_id = models.OneToOneField('Authors', models.DO_NOTHING, db_column='author_id', primary_key=True)
    book_id = models.OneToOneField('Books', models.DO_NOTHING, db_column='book_id', primary_key=True)

    class Meta:
        managed = True
        db_table = 'authors_books'
        unique_together = (('author_id', 'book_id'),)
        verbose_name_plural = 'Author Books'         


class Awards(models.Model):
    author = models.OneToOneField('Authors', models.DO_NOTHING, db_column='author', primary_key=True)
    award_name = models.CharField(max_length=45)
    year = models.IntegerField(blank=True, null=True)

    class Meta:
        managed = True
        db_table = 'awards'
        unique_together = (('author', 'award_name'),)
        verbose_name_plural = 'Awards' 


class Books(models.Model):
    titel = models.CharField(max_length=45, blank=True, null=True)
    year = models.IntegerField(blank=True, null=True)

    class Meta:
        managed = True
        db_table = 'books'
        verbose_name_plural = 'Books' 

    def __unicode__(self):
        return '{} - {}'.format(self.titel, self.year)

在AuthorsBooks类中，我将两个外键更改为OneToOneFields。

我的admin.py看起来像这样：

from django.contrib import admin
from myapp.models import Authors
...
class AwardsInline(admin.TabularInline):
    model = Awards

class AuthorsBooksInline(admin.TabularInline):
    model = AuthorsBooks

class AuthorsAdmin(admin.ModelAdmin):
    list_display = ("name", "birthday" )
    inlines = (AwardsInline, AuthorsBooksInline)

class BooksAdmin(admin.ModelAdmin):
    list_display = ("id", "titel", "year" )

admin.site.register(Authors, AuthorsAdmin)
admin.site.register(Books, BooksAdmin)

当我尝试在django管理页面上更改作者时，我收到以下错误：

Answer 1

我让它工作的唯一方法是不使用“复合”或“复合”主键。我已经添加了一个列id作为mysql表奖和authors_books的主键。 然后我改回来了：

 class AuthorsBooks(models.Model):
    author_id = models.OneToOneField('Authors', models.DO_NOTHING, db_column='author_id', primary_key=True)
    book_id = models.OneToOneField('Books', models.DO_NOTHING, db_column='book_id', primary_key=True)
    ...

要：

class AuthorsBooks(models.Model):
    author_id = models.ForeignKey('Authors', models.DO_NOTHING, db_column='author_id')
    book_id = models.ForeignKey('Books', models.DO_NOTHING, db_column='book_id') 
    ...

和

class Awards(models.Model):
    author = models.OneToOneField('Authors', models.DO_NOTHING, db_column='author', primary_key=True)
    award_name = models.CharField(max_length=45)
    year = models.IntegerField(blank=True, null=True)
    ...

到

class Awards(models.Model):
  author = models.ForeignKey('Authors2', models.DO_NOTHING, db_column='author')
  award_name = models.CharField(max_length=45)
  year = models.IntegerField(blank=True, null=True)
  ...

我找不到ManyToManyField的解决方案，总是同样的问题。 我认为原因是：

  

目前Django模型仅支持此集合中的单个列，   否认许多设计，其中表的自然主键是   多列。 Django目前无法使用这些模式;他们   必须改为引入冗余的单列密钥（“代理”   键），迫使应用程序任意和其他不必要的   选择在任何给定实例中用于表的键。

https://code.djangoproject.com/wiki/MultipleColumnPrimaryKeys