Question

您好我正在寻找一种解决方案，让我无法理解如何在查询中获得整列总数。

此查询获取工程师姓名和他们拥有的超出SLA的工作数，即工作应该已完成的数据已经过去，工作仍有待完成。

SELECT Engineer,Job_Status,COUNT(*) as 'Out Of SLA' 
FROM import 
WHERE (Job_Status = 'P' or Job_Status='P2' or Job_Status='P8') 
      and (isnull(Job_Completed_Date) 
           or Job_Completed_Date='0000-00-00') 
           and (Job_SLA_Due_Date < CURDATE()
          ) 
GROUP BY import.Engineer,Job_Status

上面的代码从导入表中产生以下结果。

+----------------+------------+------------+
|    Engineer    | Job_Status | Out of SLA |
+----------------+------------+------------+
| Andy Beeres    | P          |         15 |
| Andy Broad     | P          |          4 |
| Darren Goodwin | P          |          6 |
+----------------+------------+------------+

我希望能够显示Out of SLA列的总个数以及表数据的其余部分，如果有意义的话，如下表所示。

| Engineer      | Job_Status    | Out of SLA    |
|-------------  |------------   |------------   |
| Andy Beeres   |      P        |         14    |
|               |     P2        |          3    |
|               |     P8        |          1    |
| Total         |               |         18    |
| Andy Broad    | P             |         12    |
|               | P2            |          2    |
| Total         |               |         14    |
| Grand Total   |               |         32    |

此致

艾伦

Answer 1

将with rollup与group by一起使用以获取total_sla

根据MySql Docs：

GROUP BY子句允许WITH ROLLUP修饰符，该修饰符使得摘要输出包含表示更高级别（即超级聚合）摘要操作的额外行。因此，ROLLUP使您能够通过单个查询回答多个分析级别的问题。

SELECT Engineer,Job_Status,COUNT(*) as 'Out Of SLA' 
FROM import 
WHERE (Job_Status = 'P' or Job_Status='P2' or Job_Status='P8') 
  and (isnull(Job_Completed_Date) 
       or Job_Completed_Date='0000-00-00') 
       and (Job_SLA_Due_Date < CURDATE()
      ) 
GROUP BY import.Engineer,Job_Status WITH ROLLUP

Answer 2

一种选择是使用查找SLA总数的子查询：

SELECT Engineer,
       Job_Status,
       COUNT(*) AS `Out Of SLA`,
       (SELECT COUNT(*) FROM import) AS total_sla
FROM import
WHERE (Job_Status = 'P' OR Job_Status='P2' OR Job_Status='P8') AND
      (ISNULL(Job_Completed_Date) OR Job_Completed_Date = '0000-00-00') AND
      Job_SLA_Due_Date < CURDATE()
GROUP BY Engineer,
         Job_Status

查询所需的MYSQL总计

2 个答案: