Question

我需要在dataweave中迭代数据库查询结果并跳过重复项以及基于某些条件的少数元素。比如说，如果列订单的值是这样的： 10-ord，11-ord，12-ord，我应该只选择11-ord并跳过任何其他值以-ord结尾的行。

应该选择其余不以 - ord 结尾的值。

当前代码给出了不同的元素，但不是上面突出显示的条件。目前的代码是：

payload map ((payload, indexOfPayload) -> {
id: payload.orderId ,
number: payload.orderNumber
}) distinctBy $.number

Answer 1

使用过滤器， distinctBy 和或子句，您可以实现它

%dw 1.0
%var payload = [
    {
    "id":"value",
    "orderNumber": "10-ord"
    },
    {
    "id":"value",
    "orderNumber": "11-ord"
    },
    {
    "id":"value",
    "orderNumber": "11-ord"
    },
    {
    "id":"value",
    "orderNumber": "12-ord"
    },
    {
    "id":"value",
    "orderNumber": "13-ord"
    },
    {
    "id":"value",
    "orderNumber": "14"
    },
    {
    "id":"value",
    "orderNumber": "14"
    }
]
%output application/json
---
payload filter (not($.orderNumber contains '-ord')) or $.orderNumber =='11-ord' map ((payload, indexOfPayload) -> {
    id: payload.id ,
    number: payload.orderNumber
}) distinctBy payload.orderNumber

<强>输出

[
  {
    "id": "value",
    "number": "11-ord"
  },
  {
    "id": "value",
    "number": "14"
  }
]

除了一个

之外，删除了 -ord 的重复值和值

Answer 2

您可以根据“过滤器”子句实现它。我构建了一个示例逻辑，演示了下面的案例：

 %dw 1.0
%var payload = [
    {
    "id":"value",
    "orderNumber": "10-ord"
    },
    {
    "id":"value",
    "orderNumber": "11"
    },
    {
    "id":"value",
    "orderNumber": "12-ord"
    },
    {
    "id":"value",
    "orderNumber": "13-ord"
    },
    {
    "id":"value",
    "orderNumber": "14-ord"
    }

]
%output application/json
---
payload filter (not ($.orderNumber contains '-ord') )

Answer 3

您应该在映射之前使用过滤器以获得更好的性能。请根据您的要求尝试以下过滤器

payload filter ($.orderNumber contains '-ord') and $.orderNumber == '11-ord' map ((payload, indexOfPayload) -> {
id: payload.orderId ,
number: payload.orderNumber
})

HTH

Answer 4

%dw 1.0
%var payload = [
    {
    "id":"value",
    "orderNumber": "10-ord"
    },
    {
    "id":"value",
    "orderNumber": "11-ord"
    },
    {
    "id":"value",
    "orderNumber": "11-ord"
    },
    {
    "id":"value",
    "orderNumber": "12-ord"
    },
    {
    "id":"value",
    "orderNumber": "13-ord"
    },
    {
    "id":"value",
    "orderNumber": "26"
    },
    {
    "id":"value",
    "orderNumber": "26"
    }
    ]
%output application/json
---
payload filter (not ($.orderNumber contains '-ord')) or $.orderNumber=='11-ord' map ((payload, indexOfPayload) -> {
    id: payload.id ,
    number: payload.orderNumber
}) distinctBy payload.orderNumber

Answer 5

您可以尝试包含或子串登录，如[3..5]匹配ord并过滤JSON对象。

Mule-在dataweave中迭代Map并跳过重复元素

5 个答案: