我有一个程序Client
,它向服务器发送字符串LISTALL
。
之后,服务器需要使用ps -e
命令检查系统(Linux)上的所有正在运行的进程,然后将结果返回给客户端。
显然结果是由多个字符串组成的,那么如何让客户端接收并存储它们呢?
现在,这是我从客户那里得到的:
Message sent to the server: LISTALL
Message received from the server: null
从服务器:
Server started and listening to..
Message received from client: LISTALL
然后它按预期列出ps -e
命令的结果。
我的代码:
服务器
public class Server
{
private static Socket socket;
public static void main(String[] args)
{
try
{
int port = 25000;
ServerSocket serverSocket = new ServerSocket(port);
System.out.println("Server Started and listening to the port 25000");
//Server is running always. This is done using this while(true) loop
while(true)
{
//Reading the message from the client
socket = serverSocket.accept();
InputStream is = socket.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
BufferedReader br = new BufferedReader(isr);
String list = br.readLine();
System.out.println("Message received from client is "+list);
//Sending the response back to the client.
OutputStream os = socket.getOutputStream();
OutputStreamWriter osw = new OutputStreamWriter(os);
BufferedWriter bw = new BufferedWriter(osw);
String returnMessage;
try
{
ProcessBuilder build = new ProcessBuilder("ps", "-e");
Process proc = build.start();
BufferedReader reader = new BufferedReader(new InputStreamReader(proc.getInputStream()));
while (reader.readLine() != null) {
returnMessage=reader.readLine();
bw.write(returnMessage);
proc.waitFor();
System.out.println("Message sent to the client is "+returnMessage);
bw.flush();}
}
catch(NumberFormatException e)
{
//Input was not a number. Sending proper message back to client.
returnMessage = "Please send a proper number\n";
}
}
}
catch (Exception e)
{
e.printStackTrace();
}
finally
{
try
{
socket.close();
}
catch(Exception e){}
}
}
}
客户端:
public class Client
{
private static Socket socket;
public static void main(String args[])
{
try
{
String host = "localhost";
int port = 25000;
InetAddress address = InetAddress.getByName(host);
socket = new Socket(address, port);
//Send the message to the server
OutputStream os = socket.getOutputStream();
OutputStreamWriter osw = new OutputStreamWriter(os);
BufferedWriter bw = new BufferedWriter(osw);
String list = "LISTALL";
String sendMessage = list + "\n";
bw.write(sendMessage);
bw.flush();
System.out.println("Message sent to the server : "+sendMessage);
//Get the return message from the server
InputStream is = socket.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
BufferedReader br = new BufferedReader(isr);
while (br.readLine() != null) {
String message = br.readLine();
System.out.println("Message received from the server : " +message);
}}
catch (Exception exception)
{
exception.printStackTrace();
}
finally
{
//Closing the socket
try
{
socket.close();
}
catch(Exception e)
{
e.printStackTrace();
}
}
}
}
答案 0 :(得分:2)
您的读取循环不正确。它们应该是一般形式:
String line;
while ((line = reader.readLine()) != null) {
// Do something with `line`
}
目前你丢掉每一条奇数行,如果有奇数行,则打印一个空格。