Question

这是我正在谈论的代码的评论部分。这段代码可能看起来有点无意义，但它更复杂，我一直在简化它以找到这个问题：

void tRender(Renderer* renderer, Window* win) {
    glfwSwapInterval(1);
    while(true) {
        renderer->isBusy = true;
        renderer->draw(win); /* draws screen with a square at x position reading a var from logic */
        renderer->isBusy = false; /* same issue applies if done inside renderer->draw */
        Sleep(500); // completely arbitrary, but shows the lack of sync
    }
}

void tLogic(Logic* logic, Renderer* renderer) {
    unsigned long loops = 0;

    while (true) {
        ++loops;

        if (true) {
            ++(logic->positions[0][0]);
            printf("abc"); /* whether or not this printf exists
                              determines if it's synced */
        }

        while (renderer->isBusy) {} /* have attempted both to make it a volatile bool and
                                       a std::atomic<bool>, same results either way. */
    }
}

int main() {
    Window* win = new Window();

    Logic* logic = new Logic();
    Renderer* renderer = new Renderer(logic); /* i didn't want to use globals, so... */

    bool running = true;

    while (running) {
        std::thread threadLogic(tLogic, logic, renderer);
        tRender(renderer, win); /* GLFW rendering did not work in a thread */

        threadLogic.join();
    }

    return 0;
}

实际问题是，如果没有printf或没有std::cout（任何一个），屏幕上的可以快速移动，并且绝对不会同步实际渲染。然而，使用printf，它在很大程度上完全同步。除了printf本身之外，每个版本之间的拆卸（根据Visual Studio）都没有改变。我已经检查过，所有编译器优化选项都完全关闭了。问题可能是什么？

如果打印到控制台，多线程等待/同步代码只能正常工作

0 个答案: