Spring Security XML配置找不到我的dataSource bean定义

Question

我的WEB-INF/web.xml执行以下操作 -

1）加载我的servlet上下文 - WEB-INF/spring-web-servlet.xml

2）加载我的spring安全配置文件 - WEB-INF/spring-security.xml

3）添加springSecurityFilterChain过滤器以拦截传入的网址

web.xml

<!-- Load spring-web-service.xml Servlet Definition -->

<servlet>
  <servlet-name>spring-web</servlet-name>
  <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
  <load-on-startup>1</load-on-startup>
  <!-- Programmatically add the property sources for the current Spring Profile -->
  <init-param>
    <param-name>contextInitializerClasses</param-name>
    <param-value>com.galapagos.context.CustomEnvironmentApplicationContextInitializer</param-value>
  </init-param>
</servlet>

<servlet-mapping>
  <servlet-name>spring-web</servlet-name>
  <url-pattern>/</url-pattern>
</servlet-mapping>

<listener>
  <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<!-- Loads Spring Security config file -->

<context-param>
  <param-name>contextConfigLocation</param-name>
  <param-value>/WEB-INF/spring-security.xml</param-value>
</context-param>

<!-- Spring Security - Intercept incoming requests for authentication -->

<filter>
  <filter-name>springSecurityFilterChain</filter-name>
  <filter-class>org.springframework.web.filter.DelegatingFilterProxy
  </filter-class>
</filter>

<filter-mapping>
  <filter-name>springSecurityFilterChain</filter-name>
  <url-pattern>/*</url-pattern>
</filter-mapping>

spring-web-servlet.xml

servlet上下文实际上定义了连接到我的数据库的dataSource bean（它还预先加载了属性）

...

<!-- Load Properties -->

<beans:bean
  class="org.springframework.context.support.PropertySourcesPlaceholderConfigurer">
</beans:bean>

<!-- Database / JDBC -->

<beans:bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource">
  <beans:property name="driverClassName" value="${jdbc.driverClassName}" />
  <beans:property name="url" value="${jdbc.url}" />
  <beans:property name="username" value="${jdbc.username}" />
  <beans:property name="password" value="${jdbc.password}" />
</beans:bean>

...

spring-security.xml

问题是web.xml调用的第二个文件（我的WEB-INF/spring-security.xml文件）也使用数据库连接，因为它查找存储在数据库中的角色和凭据

<http auto-config="true" use-expressions="true">
  <intercept-url pattern="/admin**" access="hasRole('ROLE_ADMIN')" />

  <!-- access denied page -->
  <access-denied-handler error-page="/403" />

  <form-login
    login-page="/login"
    default-target-url="/"
    authentication-failure-url="/login?error"
    username-parameter="email"
    password-parameter="password" />
  <logout logout-success-url="/login?logout"  />

  <!-- enable csrf protection -->
  <csrf/>
</http>

<!-- Select users and user_roles from database -->
<authentication-manager>
  <authentication-provider>
  <jdbc-user-service
    data-source-ref="dataSource"
    users-by-username-query="SELECT email, password FROM users WHERE email=?"
    authorities-by-username-query="SELECT email, role FROM user_roles WHERE email=?" />
  </authentication-provider>
</authentication-manager>

跑步时我得到错误 -

Cannot resolve reference to bean 'dataSource' while setting bean property 'dataSource'; nested exception is org.springframework.beans.factory.NoSuchBeanDefinitionException: No bean named 'dataSource' is defined

我最好的猜测是因为dataSource是在第一个XML配置（WEB-INF/spring-web-servlet.xml）中定义的，它不适用于后者（WEB-INF/spring-security.xml）

这是对的吗？

如果是这样，定义dataSource bean的最佳方法是什么，以便所有单个XML文件可以根据需要调用它？我想我可能会在某些时候添加其他几个也需要DB访问的组件。

谢谢！

Answer 1

在web.xml中尝试更改此

  contextConfigLocation的   /WEB-INF/spring-security.xml,WEB-INF / spring-web-servlet.xml 这会对你有所帮助。