我是编程世界的新手,所以如果你们中的任何人能够帮助我在这方面变得更好,我将深表感谢。我的这个程序的目标是模拟3000个骰子卷并使用while循环计算每个不同可能的双精度对的双倍滚动次数。结果应打印在对话框中。
Random random;
random = new Random();
diceRolls = 1;
snakeEyes = 1;
doubleTwos = 1;
doubleThrees = 1;
doubleFours = 1;
doubleFives = 1;
doubleSixes = 1;
while (diceRolls <= finalDiceRoll) {
int diceRolls = 1;
int die1 = random.nextInt(6) + 1;
int die2 = random.nextInt(6) + 1;
if (die1 == 1 && die2 == 1){
//snakeEyes = snakeEyes + 1;
snakeEyes++;
}
else if (die1 == 2 && die2 == 2 ) {
doubleTwos++;
}
else if (die1 == 3 && die2 == 3) {
doubleThrees++;
}
else if (die1 == 4 && die2 == 4) {
doubleFours++;
}
else if (die1 == 5 && die2 == 5) {
doubleFives++;
}
else if (die1 == 6 && die2 == 6) {
doubleSixes++;
}
JOptionPane.showMessageDialog (null, "You rolled snake eyes " + snakeEyes + " times\nYou rolled double twos " + doubleTwos + " times\nYou"
+ " rolled double threes " + doubleThrees + " times\nYou rolled double fours " + doubleFours + " times\nYou"
+ " rolled double fives " + doubleFives + " times\nYou rolled double sixes " + doubleSixes + " times");
}
我在这里遇到的问题是,我从该计划中获得的结果似乎并不合理[&34]。例如,在3000个骰子卷中,我得到1对每双。我做错了什么?
答案 0 :(得分:1)
将showMessageDialog
移到while循环之外并递增diceRolls
变量。用0初始化所有其他整数变量
更好(更清洁和更短)的方法是使用二维数组或地图。
Random random = new Random();
int snakeEyes = 0;
int doubleTwos = 0;
int doubleThrees = 0;
int doubleFours = 0;
int doubleFives = 0;
int doubleSixes = 0;
int diceRolls = 1;
while (diceRolls <= 3000) {
int die1 = random.nextInt(6) + 1;
int die2 = random.nextInt(6) + 1;
if (die1 == 1 && die2 == 1) {
snakeEyes++;
} else if (die1 == 2 && die2 == 2) {
doubleTwos++;
} else if (die1 == 3 && die2 == 3) {
doubleThrees++;
} else if (die1 == 4 && die2 == 4) {
doubleFours++;
} else if (die1 == 5 && die2 == 5) {
doubleFives++;
} else if (die1 == 6 && die2 == 6) {
doubleSixes++;
}
diceRolls++;
}
JOptionPane.showMessageDialog(null, "You rolled snake eyes " + snakeEyes + " times\nYou rolled double twos " + doubleTwos + " times\nYou"
+ " rolled double threes " + doubleThrees + " times\nYou rolled double fours " + doubleFours + " times\nYou"
+ " rolled double fives " + doubleFives + " times\nYou rolled double sixes " + doubleSixes + " times");
上述较短版本:
Random random = new Random();
int[] doubled = new int[6];
for (int diceRolls = 0; diceRolls < 3000; diceRolls++) {
int die1 = random.nextInt(6);
int die2 = random.nextInt(6);
if (die1 == die2)
doubled[die1]++;
}
JOptionPane.showMessageDialog(null, "You rolled snake eyes " + doubled[0] + " times\nYou rolled double twos " + doubled[1] + " times\nYou"
+ " rolled double threes " + doubled[2] + " times\nYou rolled double fours " + doubled[3] + " times\nYou"
+ " rolled double fives " + doubled[4] + " times\nYou rolled double sixes " + doubled[5] + " times");
答案 1 :(得分:1)
您必须在代码中进行少量更改
1。按0
初始化所有变量。
2。将while-loop
条件更改为
while (diceRolls <= finalDiceRoll) // hoping that finalDiceRoll = 3000
3 从int diceRolls = 1;
移除while-loop
并在diceRolls++;
末尾添加while-loop
。
4。将JOptionPane
放在while-loop
之外。如果不是,你必须关闭3000 JOptionPane
dailog。
将这些更改应用到您的代码后,您将了解您做错了什么,并且您的代码运行正常。
答案 2 :(得分:0)
计数逻辑应如下:
doubleTwos = 0;
doubleThrees = 0;
doubleFours = 0;
doubleFives = 0;
doubleSixes = 0;
finalDiceRoll = 3000;
int diceRolls = 0;
while (diceRolls < finalDiceRoll) {
++diceRolls;
在循环之后发送消息。
使用数组,您可以节省输入:
int[] doubleCounts = new int[6]; // By 0 based dice values
for (int i = 0; i < finalDiceRoll; ++i) {
int die1 = random.nextInt(6); // With dice values 0-5
int die2 = random.nextInt(6);
if (die1 == die2) {
++doubleCounts[die1];
}
}
int snakeEyes = doubleCounts[0];
int doubleTwos = doubleCounts[1];
...
答案 3 :(得分:0)
简化。消除重复。当你可以使用数组时,不要使用多个变量。
int[] doubles = new int[7]; // make the index the number rolled (ignore index 0)
int diceRolls = 0;
while (diceRolls++ < 3000) {
int die1 = random.nextInt(6) + 1;
int die2 = random.nextInt(6) + 1;
if (die1 == die2)
doubles[die1]++;
}
String output = "";
for (int i = 1; i <= 6; i++)
output += "You rolled double " + i + "'s " + doubles[i] + " times\n";
JOptionPane.showMessageDialog (null, output);
这就是你所需要的一切。