Question

您可以在代码中看到vehicle（）类是一个超类。我想保留两个单独的课程（至少我认为这是最有效的方法。请指出我是否会采取相反的方式！），一个用于车辆，一个用于车辆用户，车主也列出车辆在vehicle（）类中。基本上，我将使用他们独特的ownerId向搜索所有者提供控制台输入，并且还显示关于他们的车辆类型的各种信息字段（例如mpg，最高速度，基于购买日期的转售价值等）。我想使用有效的编码实践，并将每个对象项添加到列表看起来有点尴尬。有不同的出路吗？

下面是我的vehicleOwner课程

public class VehicleOwner extends Vehicle{

    private int yearsOwned;
    private String ownerName;
    private int ownerId;

    public VehicleOwner(String ownerBrand, String ownerModelNo,int ownerModelYear, int yearsOwned, String ownerName, int ownerId) {
        super(ownerBrand, ownerModelNo, ownerModelYear);

        this.yearsOwned = yearsOwned ;
        this.ownerName = ownerName;
        this.ownerId = ownerId;

        ArrayList<VehicleOwner> list = new ArrayList<VehicleOwner>();
        VehicleOwner owner1 = new VehicleOwner("Volvo", "XC60", 2014, 3, "Mary", 00011);
        VehicleOwner owner2 = new VehicleOwner("Subaru", "crosstrek", 2015, 2, "John", 00012);
        VehicleOwner owner3 = new VehicleOwner("Mercedes", "Eseries", 2016, 1, "Brandon", 00013);
        list.add(owner1);
        list.add(owner2);
        list.add(owner3);
    }
}

Answer 1

唯一可以＆＃34;缩短＆＃34;此代码添加新对象而不为它们创建变量：

list.add(new VehicleOwner("Volvo", "XC60", 2014, 3, "Mary", 00011));
list.add(new VehicleOwner("Subaru", "crosstrek", 2015, 2, "John", 00012));
list.add(new VehicleOwner("Mercedes", "Eseries", 2016, 1, "Brandon", 00013));

Answer 2

您可以使用Arrays.asList(T...)并删除本地参考，然后请编程到List界面。像

这样的东西

List<VehicleOwner> list = new ArrayList<>(Arrays.asList( //
        new VehicleOwner("Volvo", "XC60", 2014, 3, "Mary", 00011), //
        new VehicleOwner("Subaru", "crosstrek", 2015, 2, "John", 00012), //
        new VehicleOwner("Mercedes", "Eseries", 2016, 1, "Brandon", 00013) //
));

有没有办法缩短这些命令，以便我不必重复给出list.add（对于每个所有者）？

2 个答案: