我现在一直处理个人项目,并且无法解决我在某个特定表单上遇到的问题。我在过去写过成功的Django表单,并在之后对其进行了建模,但我仍然无法显示它。
我的模型看起来像:
name = models.CharField(max_length=100)
director = models.CharField(max_length=50)
genre = models.TextField()
rating = models.IntegerField()
mpaa_rating = models.CharField(max_length=5)
# movie_file = models.FileField()
movie_cover = models.CharField(max_length=100)
cast_list = models.TextField()
year = models.TextField()
url = models.CharField(max_length=100, default='http://www.imdb.com/title/')
我的表格如下:
class Meta:
model = Movie
fields = ['url', 'name', 'director', 'genre', 'rating', 'mpaa_rating', 'movie_cover', 'cast_list', 'year']
查看:
context = RequestContext(request)
movie_form = MovieForm()
if request.method == 'POST':
movie_form = MovieForm(data=request.POST)
if movie_form.is_valid():
url = urlrequest.urlopen(movie_form.url)
movie = BeautifulSoup(url, 'html.parser')
movie_form.set_name(movie.find(itemprop='name'))
data = get_movie_data(url)
movie_form.data['name'] = data[0]
movie_form.data['director'] = data[4]
movie_form.data['genre'] = data[7]
movie_form.data['rating'] = data[3]
movie_form.data['mpaa_rating'] = data[2]
movie_form.data['year'] = data[1]
movie_form.data['cast_list'] = data[5]
movie_form.data['movie_cover'] = data[6]
movie_form.save()
print('movie added')
return render_to_response('add_movie.html', {movie_form: 'movie_form'}, context)
最后是模板:
<form id="movie_form" method="post" action="{% url 'add_movie' %}">
{% csrf_token %}
{{ movie_form.as_p }}
<input type="submit" value="Save" />
</form>
我已经阅读了关于如何解决问题的堆栈溢出的几个帖子,但是他们都没有修复我的。
感谢您的帮助
答案 0 :(得分:1)
您没有将表单发送到模板:
return render_to_response('add_movie.html', {movie_form: 'movie_form'},
替换为:
return render_to_response('add_movie.html', {'movie_form': movie_form})
更新
顺便说一句,您应该使用render()
,因为它使用RequestContext
。
如果您想在render_to_response
的模板上使用它,则必须添加参数context_instance=RequestContext(request)
,这可能有点烦人。