Question

我正在尝试以非负整数的形式收集用户输入。然后我想取这个整数并告诉用户整数中有多少个奇数，偶数和零个单位数字。

实施例。用户输入“123”并且程序输出Evens：1 Odds：2 Zeros：0

到目前为止，这是我的代码。

def main():
print("1. Enter a new number")
print("2. Print the number of odd, even and zero digits in the integer")
print("3. Print the sum of the digits of the integer")
print("4. Quit the program")

value = (input("Please enter a non-negative integer"))
Sum = 0
evens = 0
odds = 0
zeros = 0

loop=True

while loop:
    main()
    choice = int(input("Enter a number between 1 and 4:"))


    if choice==1:
        loop=False
        value = int(input("Please enter a non-negative integer"))
        loop=True

    elif choice==2:
        loop=False
        value_string = str(value)
        for ch in value_string:
            print(ch)
        for [1] in value:
            if i % 2 == 0:
                evens = evens + 1
                print(evens)

    elif choice==3:
        loop=False
        while (value >0):
            remainder = value % 10
            Sum = Sum + remainder
            value = value //10
        print("Sum of the digits = %d" %Sum)

Answer 1

您的代码严重缩进，难以理解。但你可以这样做。

value = input('enter digits ')
digits = [int(d) for d in value]
odds = sum(d % 2 for d in digits)
zeros = sum(d == 0 for d in digits)
evens = len(digits) - odds
print('evens: {}, odds: {}, zeros: {}'.format(evens, odds, zeros))

Answer 2

在这里，我有相同的代码缩进，重构和改进，以处理一些边缘情况并提供正确的结果。

def main():
    print("1. Enter a new number")
    print("2. Print the number of odd, even and zero digits in the integer")
    print("3. Print the sum of the digits of the integer")
    print("4. Quit the program")

loop = True

while loop:
    main()
    choice = str(input("Enter a number between 1 and 4: "))
    if (choice.isdigit() and 1 <= int(choice) <= 4):
        choice = int(choice)
        if choice == 1:
            value = str(input("Please enter a non-negative integer"))
            if (value.isdigit() and int(value) >= 0):
                value = int(value)
            else:
                print(
                    "You provided an invalid input. Please enter a non-negative number")
        elif choice == 2:
            value = str(value)
            odds = len([d for d in value if (int(d) % 2) == 1])
            evens = len([d for d in value if (int(d) % 2) == 0])
            zeros = len([d for d in value if d == '0'])
            print('odd: {} even: {} zeros: {}'.format(odds, evens, zeros))
        elif choice == 3:
            value = str(value)
            print('Sum of digits = {}'.format(sum(map(int, value))))
        elif choice == 4:
            print("Program is exiting")
            loop = False
    else:
        print("You provided an invalid input. Please enter a number between 1 and 4")

如何从字符串中读取单个数字并对它们执行函数？

2 个答案: