Question

我检查了十次源代码，但找不到任何错误，由于某种原因，我记得它现在正在工作它不起作用，我没有改变其他任何东西来责怪所有恶劣除了更新，当iclick编辑按钮它给出错误，意味着查询有问题。

<?php 
$editId = $_GET['id'];
$event = mysqli_query($con, "SELECT * FROM events WHERE id = '$editId'")->fetch_assoc();
if(isset($_POST['submit'])){
$name = $_POST['name'];
$description = $_POST['description'];
$date = $_POST['date'];
$artists = $_POST['artists'];
$tickets = $_POST['tickets'];
$updateQuery = mysqli_query($con, "UPDATE events SET name='$name',description='$description',date='$date', artists='$artists', ticket='$tickets' WHERE id = '$editId'");
}
?>
<?php if(isset($updateQuery) && $updateQuery): ?>
<div class="alert alert-success">
<strong>Successfully Edited</strong>
</div>
<?php endif; ?>
<?php if(isset($updateQuery) && !$updateQuery): ?>
<div class="alert alert-danger">
<strong>Error</strong>
</div>
<?php endif; ?>
<form action="<?php echo $app_host; ?>/admin/?page=editevent&id=<?php echo $editId; ?>" method="post">
<div class="form-group">
<label for="name">Name</label>
<input value="<?php echo $event['name']; ?>" required="true" type="text" class="form-control" id="name" name="name">
</div>
<div class="form-group">
<label for="description">Description</label>
<textarea class="form-control" id="description" name="description"><?php echo $event['description'];; ?></textarea>
</div>
<div class="form-group">
<label for="date">Date</label>
<input value="<?php echo $event['date']; ?>" required="true" type="text" class="form-control" id="date" name="date">
</div>
<div class="form-group">
<label for="artists">Artists</label>
<input value="<?php echo $event['artists']; ?>" required="true" type="text" class="form-control" id="artists" name="artists" data-role="tagsinput">
</div>
<div class="form-group">
<label for="tickets">Ticket Link</label>
<input value="<?php echo $event['tickets']; ?>" required="true" type="text" class="form-control" id="tickets" name="tickets" data-role="tagsinput">
</div>
<input name="submit" type="submit" class="btn btn-default" value="Edit Event" />
</form>

Answer 1

好的，你声明一个变量，

$tickets = $_POST['tickets'];

而不是你说

$updateQuery = mysqli_query($con, "UPDATE events SET name='$name',description='$description',date='$date', artists='$artists', ticket='$tickets' WHERE id = '$editId'");
}

解决方案很简单：

$updateQuery = mysqli_query($con, "UPDATE events SET name='$name',description='$description',date='$date', artists='$artists', tickets='$tickets' WHERE id = '$editId'");
}

只需将查询中的“票证”更改为“票证”。

无法使用mysqli更新查询

1 个答案: