Question

所以我正在尝试编写这个代码，该代码应该生成两个不同数字的总和，并根据所述总和确定玩家是赢了还是丢了。然后根据玩家的状态继续计算玩家的预算。我一直得到类型为“int（*）（）”的“”参数与int类型的参数不兼容“错误，我不知道为什么。

#include "stdafx.h"
#include <iostream>
#include <cmath>
#include <string>

using namespace std; 

//prototyping functions
int sum();
int bla(int, int, int, int);
void main()
{
    //declaring variables
    int budget, bet, new_budget;
    string yes_no;

    //inputting budget
    cout << "Please enter your budget: ";
    cin >> budget; 

   //inputting bet
cout << "Please enter your bet: ";
cin >> bet; 

//validating bet and budget
if (bet > budget)
{
    cout << "Error, bet cannot be larger than budget. Please reenter your budget and bet, respectively: ";
    cin >> budget;
    cin >> bet;
}
else //calling functions
{
    double m = sum();
    double n = bla(sum, budget, bet, new_budget);
}

//asks player if they would like play again
cout << "Would you like to play again? Enter Y for Yes or N for No";
cin >> yes_no;

//repeats program
if (yes_no == "Y" && (new_budget > 0))
{
    cout << "Please enter your budget: ";
    cin >> budget;

    cout << "Please enter your bet: ";
    cin >> bet;

    if (bet > budget)
    {
        cout << "Error, bet cannot be larger than budget. Please reenter your budget and bet, respectively: ";
        cin >> budget;
        cin >> bet;
    }
    else
    {
        int sum();
        bool win_or_loss(int sum, double budget, double bet);
    }
}

system("pause");
}

int sum() //calculates the sum of the dice
{
int x;
int y;
int sum;

x = rand() % 7;
y = rand() % 7;

sum = x + y;

cout << "The sum of the two dice is " << sum << endl;

return sum;
}

int bla(int sum, int budget, int bet, int new_budget) //calculates the new budget according to whether the player won or lost or neither
{
bool flag = false; 

if ((sum == 7) || (sum == 11))
{
    cout << "You have won" << endl;
    new_budget = budget + bet;
    flag = true;
}
else if ((sum == 2) || (sum == 3) || (sum == 12))
{
    cout << "You have lost" << endl;
    new_budget = budget - bet;
    flag = false;
}
else
{
    cout << "Neither win or loss, please generate new numbers" << endl;
    int sum();
    flag = false;
}

return new_budget;
}

Answer 1

int bla(int, int, int, int);

bla函数需要int个参数，但

double n = bla(sum, budget, bet, new_budget);

您正在传递sum作为参数，这是一个函数。当您的sum函数返回int时，您可以将其作为sum()传递

double n = bla(sum(), budget, bet, new_budget);

旁注：在sum内部，您已声明了名为sum的变量。避免对函数和变量使用相同的名称。这会引起歧义。

“类型为”int（*）（）“的参数与int类型的参数不兼容”错误？

1 个答案: