Question

我试图在我的班级中检索这个但是我得到了一个错误预期BEGIN_OBJECT但是STRING在第1行第1列路径$ 我对网络服务的回复是{“last_question”：“0”，“等级”：“0”，“错误”：“0”} 谢谢

的Json

select name, lat|| ', ' || lng as coords from my_table

Activtiy

    {"last_question":"0","level":"0","error":"0"}

// pojo class

    //calling from MainActivity
        private void get()
            {
                Gson gson = new GsonBuilder()
                        .setLenient()
                        .create();

                Retrofit retrofit = new Retrofit.Builder()
                        .baseUrl(BASE_URL)
                        .addConverterFactory(GsonConverterFactory.create(gson))
                        .build();

                API mApi = retrofit.create(API.class);

                Call<Example> call = mApi.getdata();
                call.enqueue(new Callback<Example>()
                {
                    @Override
                    public void onResponse(Call<Example> call, Response<Example> response)
                    {
                        System.out.println(response.body().getError());

                    }

                    @Override
                    public void onFailure(Call<Example> call, Throwable t)
                    {

                        System.out.println(t.getMessage());
                    }
                });


            }

Answer 1

更新：您的服务器没有响应您想要的响应。事实上，它返回的HTML代码：

<html><body><script type="text/javascript" src="/aes.js" ></script><script>function toNumbers(d){var e=[];d.replace(/(..)/g,function(d){e.push(parseInt(d,16))});return e}function toHex(){for(var d=[],d=1==arguments.length&&arguments[0].constructor==Array?arguments[0]:arguments,e="",f=0;f<d.length;f++)e+=(16>d[f]?"0":"")+d[f].toString(16);return e.toLowerCase()}var a=toNumbers("f655ba9d09a112d4968c63579db590b4"),b=toNumbers("98344c2eee86c3994890592585b49f80"),c=toNumbers("9cc75ba79032859c712d6ecb862cfde7");document.cookie="__test="+toHex(slowAES.decrypt(c,2,a,b))+"; expires=Thu, 31-Dec-37 23:55:55 GMT; path=/"; location.href="http://advancedcalc.byethost8.com/test.php?i=2";</script><noscript>This site requires Javascript to work, please enable Javascript in your browser or use a browser with Javascript support</noscript></body></html>

旧（错）回答：

您忘记在Example类的字段中添加@SerializedName(name)注释：

@SerializedName("last_question")
private String last_question;

@SerializedName("level")
private String level;

@SerializedName("error")
private String error;

如何使用改造2来检索json对象

1 个答案: