Question

我正试图在我们的两个仓库之间得到一个总数的qty_on_hand但是在我按总计进行分组之后不要合并。我不确定我做错了什么。

SELECT 
    sku_master.warehouse,
     sku_master.sku
   , sku_master.min_on_hand
   , sku_master.max_on_hand
   , x.total_qty_on_hand

FROM [wms].dbo.[sku_master]

left join
(
  SELECT 
     sku_master.sku, sum(location_inventory.qty_on_hand) as total_qty_on_hand
  FROM [wms].[dbo].[location_inventory]
JOIN [wms].dbo.[sku_master] ON location_inventory.sku = sku_master.sku
      GROUP BY sku_master.sku) x on sku_master.sku = x.sku

结果

ASCIIFoldingFilter

预期结果

Answer 1

您希望每个qty_on_hand的所有sku加起来。使用OUTER APPLY

尝试这样的操作

SELECT m.sku,
       m.min_on_hand,
       m.max_on_hand,
       oa.total_qty_on_hand
FROM   (SELECT sku,
               Min(min_on_hand) min_on_hand,
               Max(max_on_hand) max_on_hand
        FROM   [wms].dbo.[sku_master] m
        GROUP  BY sku) m
       OUTER Apply (SELECT Sum(l.qty_on_hand) AS total_qty_on_hand
                    FROM   [wms].[dbo].[location_inventory] l
                    WHERE  l.sku = m.sku) oa

Answer 2

如果您只需要总计，那么就不要加入，或只是为了加入一个工会这个

  SELECT 
      sku_master.warehouse,
       sku_master.sku
     , sku_master.min_on_hand
     , sku_master.max_on_hand
     , x.total_qty_on_hand

  FROM [wms].dbo.[sku_master]

  left join
  (
    SELECT 
       sku_master.sku, sum(location_inventory.qty_on_hand) as total_qty_on_hand
    FROM [wms].[dbo].[location_inventory]
  JOIN [wms].dbo.[sku_master] ON location_inventory.sku = sku_master.sku
        GROUP BY sku_master.sku) x on sku_master.sku = x.sku
  union 

  SELECT null, null, nullm null, sum(location_inventory.qty_on_hand)
  FROM [wms].[dbo].[location_inventory]
  JOIN [wms].dbo.[sku_master] ON location_inventory.sku = sku_master.sku

或者你没有对sku_master.warehouse进行分组和重复这一事实..将其从表单中删除

  SELECT 
       sku_master.sku
     , sku_master.min_on_hand
     , sku_master.max_on_hand
     , x.total_qty_on_hand

  FROM [wms].dbo.[sku_master]

  left join
  (
    SELECT 
       sku_master.sku, sum(location_inventory.qty_on_hand) as total_qty_on_hand
    FROM [wms].[dbo].[location_inventory]
  JOIN [wms].dbo.[sku_master] ON location_inventory.sku = sku_master.sku
        GROUP BY sku_master.sku) x on sku_master.sku = x.sku

Answer 3

你可以使用这个简单的查询

 SELECT 
  t.sku, 
  min(t.min_on_hand)  as min_qty_on_Hand,
  max(t.max_on_hand) as max_on_hand,
  sum(t.total_qty_on_hand) + sum(t2.total_qty_on_hand) as total_qty_on_hand
FROM table1 t
inner join table2 t2
 on t.sku = t2.sku
group by t.sku

附图显示了包含结果的过程

注意：此处的结果与您在问题中提到的相同，此处您需要将表名更改为表名

Answer 4

在您的请求评论中，您解释说您更喜欢一个仓库而不是另一个仓库。在这种情况下，您应该有一个包含仓库的表，其中包含优先级列。因此，查询不必了解仓库优先级。（想象一下你有一天会添加一个仓库 - 你必须改变所有的查询。）

我的查询汇总每个SKU和仓库的sku_master记录，然后根据SKU选择最佳仓库。然后它通过SKU加入汇总的库存行。

这是没有仓库表的查询。

select
  m.warehouse,
  m.sku,
  m.total_min_on_hand,
  m.total_max_on_hand,
  li.total_qty_on_hand
from
(
  select 
    sku, 
    warehouse,
    sum(min_on_hand) as total_min_on_hand,
    sum(max_on_hand) as total_max_on_hand,
    row_number() over (partition by sku 
                       order by case when warehouse = 'XDGM'  then 1 else 2 end) as rn
  from sku_master
  group by sku
) m
join
(
  select sku, sum(qty_on_hand) as total_qty_on_hand
  from location_inventory
  group by sku
) li on li.sku = m.sku
where m.rn = 1; -- only the better warehouse when there is more than one for the SKU

对于仓库表，from子句会稍微改为：

from
(
  select 
    sku, 
    warehouse,
    sum(min_on_hand) as total_min_on_hand,
    sum(max_on_hand) as total_max_on_hand,
    row_number() over (partition by sku order by w.priority) as rn
  from sku_master sm
  join warehouse w on w.warehouse = sm.warehouse
  group by sku
) m

在分组依据之后，SQL仍然有重复项

4 个答案: