Question

如何通过java在appium测试中长按特定时间的Android记录按钮。我尝试了两种方法，但两种方法都没有用，那些方法是：

方式1：

By pressRecBtn = By.id("recorderButton");
int x = 353;  // x coordinate of device screen, get it after enabling the Show touch and Pointer location from developer option 
int y = 980; // same as x
int timeInMs = 4000;

Action.longPress(driver.findElement(pressRecBtn)).longPress(x, y, timeInMs).perform();

方式2：

By pressRecBtn = By.id("recorderButton");
int timeInMs = 4000;

Action.longPress(driver.findElement(pressRecBtn)).waitAction(timeInMs).perform();

以这种方式按下rec按钮但是默认时间（＆gt; = 1000 MS）。

Answer 1

你可以这样试试，

 TouchAction Action = new TouchAction(driver);
 Action.longPress(driver.findElement(By.name("xyz"))).perform();

Answer 2

它的工作很酷!!

By tapOnRecIcon = By.id("btnRecord");    
int timeInMs = 4000;
TouchAction touchAction = new TouchAction((MobileDriver) driver);

touchAction.longPress(driver.findElement(pressRecBtn),timeInMs).release().perform();

Answer 3

public void longClick(String element) {
        // TODO Auto-generated method stub
        WebElement webElement = appiumDriver.findElement(By.xpath(element));

        TouchAction Action = new TouchAction(appiumDriver);
        Action.longPress(webElement).release().perform();
    }

如何通过java在appium测试中长时间按下Android记录按钮（在聊天期间）特定的持续时间

3 个答案: