我想读取和写入文件的对象。这是我的尝试:
import java.io.BufferedInputStream;
import java.io.BufferedOutputStream;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.ObjectInputStream;
import java.io.ObjectOutputStream;
import java.io.Serializable;
import java.util.ArrayList;
public class SaveOpen implements Serializable
{
private static String fileName;
private ArrayList<Person> list = new ArrayList<Person>();
public SaveOpen() {
fileName = "file.txt";
}
//Reader
public static Object deserialize() throws IOException,
ClassNotFoundException {
FileInputStream fis = new FileInputStream(fileName);
BufferedInputStream bis = new BufferedInputStream(fis);
ObjectInputStream ois = new ObjectInputStream(bis);
Object obj = ois.readObject();
ois.close();
return obj;
}
//Writer
public static void serialize(Object obj)
throws IOException {
FileOutputStream fos = new FileOutputStream(fileName);
BufferedOutputStream bos = new BufferedOutputStream(fos);
ObjectOutputStream oos = new ObjectOutputStream(bos);
oos.writeObject(obj);
oos.close();
}
public void setFileName(String fileName) {
this.fileName = fileName;
}
public ArrayList<Person> getListPersons() {
return list;
}
}
但是,我不知道这是否是正确的方法,也不知道如何在课堂上实现这一点。对象是Person
,我想从文件中保存并读取该对象。应该对.txt
文件进行吗?谁可以澄清事情?谢谢!
答案 0 :(得分:0)
如果您希望文件是人类可读的,我建议将其保存为xml。
示例:
对象类
import java.io.Serializable;
public class Person implements Serializable
{
private String username;
private int id;
public String UserName() { return username; }
public void setUserName(String str) { username = str;}
public int ID() { return id; }
public void setID(int ID) { id = ID; }
}
-Serializer /解串器
import Settings.Person;
import java.beans.XMLDecoder;
import java.beans.XMLEncoder;
import java.io.ByteArrayInputStream;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
public class XmlSerializer
{
//File path to serialize to and deserialize from
private static final String SERIALIZED_FILE_NAME = "yourSavePath.xml";
//Insert person object and save as xml file to chosen filepath
public static void Serialize(Person person)
{
try
{
FileOutputStream os = new FileOutputStream(SERIALIZED_FILE_NAME);
XMLEncoder encoder = new XMLEncoder(os);
encoder.writeObject(person);
encoder.close();
}
catch(FileNotFoundException ex)
{
System.out.println(ex.getMessage());
}
}
//Deserialize xml file into person object
public static Person Deserialize()
{
try
{
FileInputStream os = new FileInputStream(SERIALIZED_FILE_NAME);
XMLDecoder decoder = new XMLDecoder(os);
Person p = (Person)decoder.readObject();
decoder.close();
return p;
}
catch(FileNotFoundException ex)
{
System.out.println(ex.getMessage());
}
return null;
}
}
答案 1 :(得分:0)
你已经做对了。您可以在txt文件中保护对象,尽管它没有多大意义,我宁愿使用二进制文件。
要将多个对象存储在单个文件中,只需将它们打包在Collection中,然后序列化Collection对象即可。
从文件中读取对象时,通过instanceof检查其类,并将其转换为任何类型。