我有一个Json文件' extract.json',我获取循环结果的内容,但我的代码只返回一行,我的脚本==>
$filename = "extract.json";
$str = file_get_contents($filename);
if($str!=null) {
$decoded=json_decode($str,true);
$compteur = 0;
$compteur = count($decoded);
if(is_array($decoded)) {
foreach($decoded as $value) {
$var1= $value["val1"];
$var2 = $value["val2"];
$var3 = $value["val3"];
$var4 = $value["val4"];
$var5 = $value["val5"];....
$injection_final = "INSERT INTO `Table`(
`var1`,
`var2`,
`var3`,
`var4`,
`var5`,)
VALUES
($var1,$var2,$var3,$var4,$var5)";
$inj = mysqli_query($con1,$injection_final);
}
}
}
MY JSON FILE ==>
[{"val1":"1","val2":"2","val3":"0000-00-00","val4":"1","val5":"1939-05-08"},{"val1":"1","val2":"2","val3":"0000-00-00","val4":"1","val5":"1939-05-08"},{"val1":"1","val2":"2","val3":"0000-00-00","val4":"1","val5":"1939-05-08"},{"val1":"1","val2":"2","val3":"0000-00-00","val4":"1","val5":"1939-05-08"},{"val1":"1","val2":"2","val3":"0000-00-00","val4":"1","val5":"1939-05-08"}...]
答案 0 :(得分:1)
问题在于您的sql,so it should not insert even a single row
。你正在使用日期,但没有把它们放在引号中。试试如下:
$filename = "extract.json";
$str = file_get_contents($filename);
if($str!=null){
/////.....rest of your code
$var1= $value["val1"];
$var2 = $value["val2"];
$var3 = $value["val3"];
$var4 = $value["val4"];
$var5 = $value["val5"];
$injection_final = "INSERT INTO Table(var1,var2,var3,var4,var5,)
VALUES($var1,$var2,'$var3',$var4,'$var5')";
echo $injection_final."<br>";//use this query to insert
......
}
答案 1 :(得分:1)
<?php
$json_data = '[{"val1":"1","val2":"2","val3":"0000-00-00","val4":"1","val5":"1939-05-08"},{"val1":"1","val2":"2","val3":"0000-00-00","val4":"1","val5":"1939-05-08"},{"val1":"1","val2":"2","val3":"0000-00-00","val4":"1","val5":"1939-05-08"},{"val1":"1","val2":"2","val3":"0000-00-00","val4":"1","val5":"1939-05-08"},{"val1":"1","val2":"2","val3":"0000-00-00","val4":"1","val5":"1939-05-08"}]';
//uncomment the below line to read from file
//$json_data = file_get_contents("extract.json");
$array_data = json_decode($json_data, true);
for ($i = 0; $i < count($array_data); $i++) {
$table_column_names = "";
$table_column_values = "";
foreach ($array_data[$i] as $coulmn_name => $field_value) {
$table_column_names .= "`$coulmn_name`, ";
$table_column_values .= "'$field_value', ";
}
$table_column_names = rtrim($table_column_names, ", ");
$table_column_values = rtrim($table_column_values, ", ");
$sql_query = "INSERT INTO `Table` ($table_column_names) VALUES ($table_column_values)";
//excute query here -- like if i just print the query
echo $sql_query."\n";
}
这是您需要的......它将执行所有行 输出:
INSERT INTO `Table` (`val1`, `val2`, `val3`, `val4`, `val5`) VALUES ('1', '2', '0000-00-00', '1', '1939-05-08')
INSERT INTO `Table` (`val1`, `val2`, `val3`, `val4`, `val5`) VALUES ('1', '2', '0000-00-00', '1', '1939-05-08')
INSERT INTO `Table` (`val1`, `val2`, `val3`, `val4`, `val5`) VALUES ('1', '2', '0000-00-00', '1', '1939-05-08')
INSERT INTO `Table` (`val1`, `val2`, `val3`, `val4`, `val5`) VALUES ('1', '2', '0000-00-00', '1', '1939-05-08')
INSERT INTO `Table` (`val1`, `val2`, `val3`, `val4`, `val5`) VALUES ('1', '2', '0000-00-00', '1', '1939-05-08')
答案 2 :(得分:1)
这一行的简单改变
来自$var1,$var2,$var3,$var4,$var5)";
到
('$var1', '$var2', '$var3', '$var4', '$var5')";
答案 3 :(得分:0)
您的JSON数组的格式不正确。有关示例,请参阅以下链接: