Question

我有一张这样的表：

name | action      |    action_timestamp
------------------------------------------
ABC  | START_PLAY  |  2017-02-02 10:00:00
PQR  | START_PLAY  |  2017-02-02 11:00:00
ABC  | END_PLAY    |  2017-02-02 10:30:00
PQR  | END_PLAY    |  2017-02-02 11:05:00

我希望获得所有已经开始在给定时间戳之后或之后播放的名字，并在给定时间戳之前或之前结束播放。

例如，如果（action =＆＃39; START_PLAY＆＃39;和action_timestamp＆gt; = 2017-02-02 10:00:00）和（action =＆＃39; END_PLAY＆＃39;和action_timestamp＆lt; = 2017-02-02 10:30:00）然后查询应该返回ABC

我不确定应该如何制作条件（即start_play和action_timestamp）。

Answer 1

试试这个：

GraphStage

Answer 2

假设每个"acorn": { "version": "4.0.4", "from": "acorn@>=4.0.4 <5.0.0", "resolved": "https://registry.npmjs.org/acorn/-/acorn-4.0.4.tgz" },确实存在name的一行和START_PLAY的一行，您可以使用以下内容：

END_PLAY

嵌套查询对表执行单次扫描，并为每个select name, start_play, end_play from ( select name, max ( case when action = 'START_PLAY' then action_timestamp end) as start_play, max ( case when action = 'END_PLAY' then action_timestamp end) as end_play from yourTable group by name ) where start_play > ... and end_play < ...创建一行，行上有name和start_play;外部部分只是对内部查询产生的行应用过滤器。

Answer 3

试试这个：

select data.name from 
  (SELECT NAME,ACTION,ACTION_TIMESTAMP, ROW_NUMBER() OVER(PARTITION BY NAME ORDER BY ACTION) AS count FROM ST3 
  where (action='START_PLAY' AND ACTION_TIMESTAMP>='02-FEB-17 10.00.00')OR 
  (ACTION='END_PLAY' AND ACTION_TIMESTAMP<='02-FEB-17 10.30.00')) data
where data.count=2;

Answer 4

像这样使用相交：

SELECT DISTINCT name FROM TBL WHERE action='START_PLAY' and action_timestamp >= '2017-02-02 10:00:00'
INTERSECT
SELECT DISTINCT name FROM TBL WHERE action='END_PLAY' and action_timestamp <= '2017-02-02 10:30:00'

SQL查询一对字段在一起

4 个答案: