我在思考如何使用位于前方的线索词来选择最佳候选者。这应该在字符串集中运行,我试图多次实现,但是无法做到。
基本概念是有这样的字符串' ----- clueword(candiate1 | candidate2 ...)----'我想要的功能可以根据数据选择最有希望的候选者。
clue = c( 'a', 'to', 'a', 'to', 'to')
word = c('house','school','paper','water','schooling')
cooccur = c(100, 90, 83, 70, 61)
data = data.frame(clue,word,cooccur)
假设有两个字符串集
S1 = 'I have a (house|water|paper) and car'
S2 = 'I need to go to (school|schooling) right now'
线索词' a'与“房子”共同发生的频率很高,而且“与房子的关系很频繁”。和学校一起做#39;因此,使用THE函数,结果应该是
S1
[1] 'I have a (house) and car'
S2
[2] 'I need to go to (school) right now'
您不必担心处理删除不太有希望的候选人,因为此代码会处理此问题。
library(gsubfn)
gsubfn("\\(([^)]+)", ~paste0("(", paste(THEFUNCTION(unlist(x)), collapse="|")), S1)
我知道我可以使用which.max()
但是使用它与“线索”相关联一点也不容易。有什么方法可以让我通过这个吗?
答案 0 :(得分:0)
这有效:
THEFUNCTION <- function(x) { # dummy function, to be replaced by the one that selects w.r.t. co-occurence frequency
# this function receives inputs without paranthesis: e.g., 'house|water|paper'
ifelse(grepl('house', x), 'house', 'school')
}
S1 = 'I have a (house|water|paper) and car'
S2 = 'I need to go to (school|schooling) right now'
library(gsubfn)
gsubfn("\\(([^\\)]+)\\)", ~paste0("(", paste(THEFUNCTION(unlist(x)), collapse="|"), ")"), S1)
#[1] "I have a (house) and car"
gsubfn("\\(([^\\)]+)\\)", ~paste0("(", paste(THEFUNCTION(unlist(x)), collapse="|"), ")"), S2)
#[1] "I need to go to (school) right now"