我在父组件中有一个按钮。我想通过单击该按钮来聚焦位于子组件中的输入字段。我怎么能这样做。
答案 0 :(得分:14)
您可以使用refs
来获得结果
class Parent extends React.Component {
handleClick = () => {
this.refs.child.refs.myInput.focus();
}
render() {
return (
<div>
<Child ref="child"/>
<button onClick={this.handleClick.bind(this)}>focus</button>
</div>
)
}
}
class Child extends React.Component {
render() {
return (
<input type="text" ref="myInput"/>
)
}
}
ReactDOM.render(<Parent/>, document.getElementById('app'));
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>
<div id="app"></div>
更新:
React docs建议使用ref callback
而不是string refs
class Parent extends React.Component {
handleClick = () => {
this.child.myInput.focus();
}
render() {
return (
<div>
<Child ref={(ch) => this.child = ch}/>
<button onClick={this.handleClick.bind(this)}>focus</button>
</div>
)
}
}
class Child extends React.Component {
render() {
return (
<input type="text" ref={(ip)=> this.myInput= ip}/>
)
}
}
ReactDOM.render(<Parent/>, document.getElementById('app'));
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>
<div id="app"></div>
答案 1 :(得分:1)
不是从父级访问子组件的输入元素,而是公开如下方法,
class Parent extends React.Component {
handleClick = () => {
this.refs.child.setFocus();
};
render() {
return (
<div>
<Child ref="child"/>
<button onClick={this.handleClick.bind(this)}>focus</button>
</div>
)
}
}
class Child extends React.Component {
setFocus() {
this.refs.myInput.focus();
}
render() {
return (
<input type="text" ref="myInput"/>
)
}
}
ReactDOM.render(<Parent/>, document.getElementById('app'));
答案 2 :(得分:1)
您可以简单地在子组件中使用componentDidMount(),如下所示
class Child extends React.Component {
componentDidMount() {
this.myInput.focus()
}
render() {
return (
<input type="text" ref={(input)=> this.myInput= input}/>
)
}
}