Question

根本不打印与上面一行相同的输出，我无法弄清楚为什么会发生这种情况，我注意到它从最后向后打印最后N个数字，无论我输入它打印的参数第二次。

这是主要的

import java.util.ArrayList;
import java.util.Random;

public class ScalesSolution {
private String scasol;

public void print() {
    System.out.print(scasol);
}

// Display the string with a new line
public void println() {
    print();
    System.out.println();
}



public String GetSol()
{
    return scasol;
}
}

继承人ScalesSolution类

import java.util.*;
import java.io.*;

public class randomOther {
// Shared random object
static private Random rand;

// Create a uniformly distributed random integer between aa and bb inclusive
static public int UI(int aa, int bb) {
    int a = Math.min(aa, bb);
    int b = Math.max(aa, bb);
    if (rand == null) {
        rand = new Random();
        rand.setSeed(System.nanoTime());
    }
    int d = b - a + 1;
    int x = rand.nextInt(d) + a;
    return (x);
}

// Create a uniformly distributed random double between a and b inclusive
static public double UR(double a, double b) {
    if (rand == null) {
        rand = new Random();
        rand.setSeed(System.nanoTime());
    }
    return ((b - a) * rand.nextDouble() + a);
}
static public ArrayList<Double> ReadNumberFile(String filename) {
    ArrayList<Double> res = new ArrayList<Double>();
    Reader r;
    try {
        r = new BufferedReader(new FileReader(filename));
        StreamTokenizer stok = new StreamTokenizer(r);
        stok.parseNumbers();
        stok.nextToken();
        while (stok.ttype != StreamTokenizer.TT_EOF) {
            if (stok.ttype == StreamTokenizer.TT_NUMBER) {
                res.add(stok.nval);
            }
            stok.nextToken();
        }
    } catch (Exception E) {
        System.out.println("+++ReadFile: " + E.getMessage());
    }
    return (res);
}
}

继承了RandomOther Class

00101001010101101011001011010101101001011010001011010010101101001001011010010
01011010010

以下是输出问题：

$myTableArray = json_decode($_POST['myTableArray'], true);

$appointment_id=$this->user_model->get_details();

$details=$this->user_model->patient_investigation_details($myTableArray,$appointment_id);

我相信两个输出应该是相同的，我发现这里有一个问题，不确定它们为什么不是

Answer 1

我发现您在System.out.print内使用RandomBinaryString(int n)的方式导致了混淆。它正在打印并附加到字符串s。尽量避免这种情况。将System.out.print(s += '0');和System.out.print(s += '1');替换为s += '0';中的s += '1';和RandomBinaryString将会修复您的输出。

在代码中使用以下代码段：

private static String RandomBinaryString(int n) {
    String s = new String();

    // Code goes here
    // Create a random binary string of just ones and zeros of length n
    for (int i = 0; i < n; i++) {
        int y = randomOther.UI(0, 1);
        if (y == 0) {
            s += '0';// this line here was changed
        } else {
            s += '1';// and this line here was changed too
        }
    }

    return (s);
}

希望这有帮助！

不打印相同的输出

1 个答案: