XML到XML表使用XSLT进行@rowspan转换转换

Question

我有一个XML：

    <?xml version="1.0" encoding="UTF-8"?>
    <table>
        <tr>
             <td rowspan="1">0</td>
             <td rowspan="3">1</td>
             <td rowspan="1">2</td>
             <td rowspan="2">3</td>
             <td rowspan="1">4</td>
             <td rowspan="1">5</td>
             <td rowspan="2">6</td>
             <td rowspan="2">7</td>
             <td rowspan="1">8</td>
             <td rowspan="2">9</td>
        </tr>
        <tr>
             <td rowspan="1">10</td>
             <td rowspan="1">11</td>
             <td rowspan="1">12</td>
             <td rowspan="1">13</td>
             <td rowspan="1">14</td>
        </tr>
        <tr>
             <td rowspan="1">15</td>
             <td rowspan="1">16</td>
             <td rowspan="1">17</td>
             <td rowspan="1">18</td>
             <td rowspan="1">19</td>
             <td rowspan="1">20</td>
             <td rowspan="1">21</td>
             <td rowspan="1">22</td>
             <td rowspan="1">23</td>
        </tr>
    </table>

哪个应转换为：

    <?xml version="1.0" encoding="UTF-8"?>
    <table>
        <tr>
             <td rowspan="1">0</td>
             <td rowspan="3">1</td>
             <td rowspan="1">2</td>
             <td rowspan="2">3</td>
             <td rowspan="1">4</td>
             <td rowspan="1">5</td>
             <td rowspan="2">6</td>
             <td rowspan="2">7</td>
             <td rowspan="1">8</td>
             <td rowspan="2">9</td>
        </tr>
        <tr>
             <td rowspan="1">10</td>
             <row-span-anchor/>
             <td rowspan="1">11</td>
             <row-span-anchor/>
             <td rowspan="1">12</td>
             <td rowspan="1">13</td>
             <row-span-anchor/>
             <row-span-anchor/>
             <td rowspan="1">14</td>
             <row-span-anchor/>
        </tr>
        <tr>
             <td rowspan="1">15</td>
             <row-span-anchor/>
             <td rowspan="1">16</td>
             <td rowspan="1">17</td>
             <td rowspan="1">18</td>
             <td rowspan="1">19</td>
             <td rowspan="1">20</td>
             <td rowspan="1">21</td>
             <td rowspan="1">22</td>
             <td rowspan="1">23</td>
        </tr>
    </table>

要求是有任何@rowspan元素，应该在转换后的XML中的相应位置转换为类似<row-span-anchor/>的内容。

可以使用XSLT2实现吗？

注意：如果td[@rowspan > 1]，则<row-span-anchor/>应放在下一行的td（或连续的行）上。例如：/table/tr[1]/td[2]有@rowspan=3，然后<row-span-anchor/>应放在/table/tr[2]/td[1]和/table/tr[3]/td[1]之后。在第一行 - 第四，第七，第八和第十列（td）中有@rowspan=2，因此在第二行（/table/tr[2]）<row-span-anchor/>被放置。