Question

我在文件中有这个：

当行为'-'时，我需要将每个分割成自己的矩阵。到目前为止我做了什么：

    with open(fname) as f:
        content = f.readlines()
        subArray = []
        firstMatrix= []
        for line in content:
            if line.strip() == '-':
                break
            for digit in line.split():
                subArray.append(digit)
            firstMatrix.append(subArray)

但是将'-'之前的矩阵的所有数字放入数组数组中。我尝试在其中插入if line == '-' break，但无济于事。最终输出需要是：

[[1, 0, 2, 4, 3],
[4, 6, 5, 2, 1],
[4, 4, 5, 2, 1],
[5, 6, 8, 5, 3]]

[[3, 2, 4, 0],
[3, 2, 4, 2],
[0, 7, 3, 3],
[3, 3, 0, 2],
[1, 3, 2, 2]]

每个都保存到各自的变量中：firstMatrix，secondMatrix。

Answer 1

假设文件的全部内容都是可变内容

url(ur'^reply/(.*)/?$', views.visit),

Answer 2

您可以将其实现为生成器。

def get_matrix(filename):
    with open(filename, 'r') as fin:
        matrix = []
        for line in fin:
            line = line.strip()
            if line == '-':
                yield matrix
                matrix = []
            else:        
                matrix.append([int(i) for i in line.split()])
        else:
            yield matrix # yield last matrix in case file doesn't end with '-'

>>> for m in get_matrix('matrix_file.txt'):
    print(m)

[[1, 0, 2, 4, 3], [4, 6, 5, 2, 1], [4, 4, 5, 2, 1], [5, 6, 8, 5, 3]]
[[3, 2, 4, 0], [3, 2, 4, 2], [0, 7, 3, 3], [3, 3, 0, 2], [1, 3, 2, 2]]

Answer 3

current = 0
curr_mat = []
all_matrix = []

with open(fname) as f:
   line = f.readlines()
   line = line.split()
   if len(line) == 1 and line[0] == '-':
       count += 1
       all_matrix.append(curr_mat)
       curr_mat = []

   else:
       curr_mat.append(line)

all_matrix将处理后的所有矩阵，索引0将具有matrix0，1索引将具有matrix1，依此类推。

Answer 4

你不能在列表理解中使用break

您应首先处理数据

B2

matrix [0]包含第一个矩阵.. etc

Answer 5

这很有效。

将所有矩阵保存到数组而不是变量名。

f = open('file1.txt')

matrices = []

matrix = []
for line in f.readlines():
  str = line.translate(None, '\n\r ')
  if(str[0] != '-'):
    matrix.append(list(str))
  else:
    matrices.append(matrix)
    matrix = []

#depends if code ends in '-' char
matrices.append(matrix)

print(matrices)

Answer 6

您永远不会在代码中重置subArray：

for digit in line.split():
    subArray.append(digit)
firstMatrix.append(subArray)

因此subArray将包含矩阵中的所有数字。

试试这个：

matrices = [[] for _ in range(2)] # since you only have 2 matrices in text file
no_matrix = 0                     # matrices[no_matrix], you get the idea

with open(fname) as f:
    content = f.readlines()
    for line in content:
        subArray = []
        if line.strip() == '-':
            no_matrix += 1
        else:
            for digit in line.split():
                subArray.append(digit)
            matrices[no_matrix].append(subArray)

for matrix in matrices:
    print(matrix)

干杯！

Answer 7

这对我有用：

txt = open('stackFile.txt')
file = txt.read()
splitedFile = file.split(' ')
# print m
allmatrix = []
data = []
c = list()
for n in splitedFile:

    # print "n",n
    if '\n' in n:
        if '-' in n:
            v = n.split('\n-\n')
            c.append(v[0])          
            data.append(c)
            allmatrix.append(data)
            c = list()
            data = list()
            c.append(v[1])


        else:

            v = n.split('\n')
            c.append(v[0])          
            data.append(c)
            c = list()
            c.append(v[1])

    else:
        c.append(n)
updateFinalMatrix = allmatrix.append(data)

for matrix in allmatrix:
    print matrix

Answer 8

这只是对@Arjun的帖子的澄清（即在短划线末尾注明没有“\ n”）：

import re
content="\
1 0 2 4 3\n\
4 6 5 2 1\n\
4 4 5 2 1\n\
5 6 8 5 3\n\
-\
3 2 4 0\n\
3 2 4 2\n\
0 7 3 3\n\
3 3 0 2\n\
1 3 2 2\n"

matrices = re.split('-', content)
firstMatrix, secondMatrix = [[mat.split() for mat in matrix.splitlines()] for matrix in matrices]
print(firstMatrix,"\n",secondMatrix)

这为您提供了所需的答案：

[['1', '0', '2', '4', '3'], ['4', '6', '5', '2', '1'], ['4', '4', '5', '2', '1'], ['5', '6', '8', '5', '3']]
[['3', '2', '4', '0'], ['3', '2', '4', '2'], ['0', '7', '3', '3'], ['3', '3', '0', '2'], ['1', '3', '2', '2']]

从文件中将数字解析为两个2D数组

8 个答案: