Question

def squares(start, num):
    s_sum = 0
    for i in range(num):
        s_sum += start**2
        start += 1
    return s_sum
command = input("Enter a command: ")
while command == 'squares' :
    a = int(input("Enter initial integer: "))
    b = int(input("Enter the number of terms: "))
    sq_sum = squares(a, b)
    print('Sum = ', sq_sum)

我想知道如何打印出求和线（例如：Sum = 2**2 + 3**2 + 4**2 + 5**2 = 54）。我的代码只打印出Sum = 54。

Answer 1

您可以使用for循环生成字符串"number**2"并保留在列表中，稍后您可以使用' + '.join(list)来连接此字符串

def squares(start, num):
    s_sum = 0
    for i in range(num):
        s_sum += start**2
        start += 1
    return s_sum

a = int(input("Enter initial integer: "))
b = int(input("Enter the number of terms: "))
sq_sum = squares(a, b)

terms = []

for number in range(a, a+b):
    terms.append("{}**2".format(number))

terms = ' + '.join(terms)

print(terms, '=', sq_sum)

编辑或更短：

a = int(input("Enter initial integer: "))
b = int(input("Enter the number of terms: "))

sq_sum = sum(i**2 for i in range(a, a+b))

terms = ' + '.join("{}**2".format(i) for i in range(a, a+b))

print(terms, '=', sq_sum)

Answer 2

您也可以更改squares()以返回字符串。

def squares(start, num):
    s_sum = 0
    output = ""
    for i in range(num):
        s_sum += start**2
        output += '{}**2+'.format(start)
        start += 1
    return s_sum, output[:-1]

如何打印求和线

2 个答案: