我有一个对象数组
"fields": [
{
"label": "Country",
"name": "country",
"picklistValues": ["USA", "CAN"],
"type": "string"
},
{
"label": "Day",
"name": "day",
"picklistValues": ["Monday", "Tuesday", "Wednesday"],
"type": "string"
},
{...},
]
使用此代码
renderTerritoryMeta() {
return this.props.territoryMeta.map((territoryField) => {
return (
<div className="slds-grid slds-box slds-box--x-small tile">
{territoryField.label}
</div>
);
});
}
它渲染数组中的所有对象。我希望按键name
加上值获取特定对象,然后获取同一对象的picklistValues
。
// with this array
// get the object by key 'name' & value 'country'
// then with same object get values from key 'pickListValues'
答案 0 :(得分:1)
您可以在div渲染之前使用条件 我会尝试这样的事情:
renderTerritoryMeta() {
return this.props.territoryMeta.map((territoryField) => {
const shouldRender = territoryField.name === 'country'
let pickListValues = []
if (shouldRender) pickListValues = territoryField.pickListValues
if (!shouldRender) return null
return (
<div className="slds-grid slds-box slds-box--x-small tile">
{territoryField.label}
</div>
);
});
}
答案 1 :(得分:0)
当name = country时短路地图。
<abbr class="timeago">